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Sagot :
Let's walk through the replacement reaction step by step to determine the products formed when Barium nitrate [tex]\(\text{Ba}(\text{NO}_3)_2\)[/tex] reacts with Sodium sulfate [tex]\(\text{Na}_2\text{SO}_4\)[/tex].
1. Identify the Reactants:
- The reactants are Barium nitrate [tex]\(\text{Ba}(\text{NO}_3)_2\)[/tex] and Sodium sulfate [tex]\(\text{Na}_2\text{SO}_4\)[/tex].
2. Determine the Cations and Anions:
- In Barium nitrate [tex]\(\text{Ba}(\text{NO}_3)_2\)[/tex], the cation is [tex]\(\text{Ba}^{2+}\)[/tex] and the anion is [tex]\(\text{NO}_3^-\)[/tex].
- In Sodium sulfate [tex]\(\text{Na}_2\text{SO}_4\)[/tex], the cations are [tex]\(\text{Na}^+\)[/tex] and the anion is [tex]\(\text{SO}_4^{2-}\)[/tex].
3. Swap the Cations:
- The [tex]\(\text{Ba}^{2+}\)[/tex] will pair with the [tex]\(\text{SO}_4^{2-}\)[/tex] to form Barium sulfate ([tex]\(\text{BaSO}_4\)[/tex]).
- The two [tex]\(\text{Na}^+\)[/tex] will pair with the two [tex]\(\text{NO}_3^-\)[/tex] to form Sodium nitrate ([tex]\(\text{NaNO}_3\)[/tex]).
4. Write the Unbalanced Equation:
- [tex]\(\text{Ba}(\text{NO}_3)_2 + \text{Na}_2\text{SO}_4 \rightarrow \text{NaNO}_3 + \text{BaSO}_4\)[/tex]
5. Balance the Chemical Equation:
- To balance the equation, ensure that the same number of each type of atom appears on both sides. We have:
[tex]\[ \text{Ba}(\text{NO}_3)_2 + \text{Na}_2\text{SO}_4 \rightarrow 2\text{NaNO}_3 + \text{BaSO}_4 \][/tex]
- Now, the equation is balanced with:
- 1 Barium atom on each side,
- 2 Nitrate ions on each side,
- 2 Sodium atoms on each side,
- 1 Sulfate ion on each side.
6. Determine the Products:
- The balanced chemical equation confirms that the products are Sodium nitrate ([tex]\(\text{NaNO}_3\)[/tex]) and Barium sulfate ([tex]\(\text{BaSO}_4\)[/tex]).
So, during the replacement reaction of [tex]\(\text{Ba}(\text{NO}_3)_2\)[/tex] and [tex]\(\text{Na}_2\text{SO}_4\)[/tex], the products formed are [tex]\(\text{NaNO}_3\)[/tex] and [tex]\(\text{BaSO}_4\)[/tex].
Reviewing the answer choices:
- [tex]\(2 \text{BaNa} + 2 \text{NO}_3\text{SO}_4\)[/tex]
- [tex]\(2 \text{NaNO}_3 + \text{BaSO}_4\)[/tex]
- [tex]\(\text{NaNO}_3 + \text{BaSO}_4\)[/tex]
- [tex]\(\text{BaNa}_2 + (\text{NO}_3)_2\text{SO}_4\)[/tex]
The correct answer is:
[tex]\[ 2 \text{NaNO}_3 + \text{BaSO}_4 \][/tex]
1. Identify the Reactants:
- The reactants are Barium nitrate [tex]\(\text{Ba}(\text{NO}_3)_2\)[/tex] and Sodium sulfate [tex]\(\text{Na}_2\text{SO}_4\)[/tex].
2. Determine the Cations and Anions:
- In Barium nitrate [tex]\(\text{Ba}(\text{NO}_3)_2\)[/tex], the cation is [tex]\(\text{Ba}^{2+}\)[/tex] and the anion is [tex]\(\text{NO}_3^-\)[/tex].
- In Sodium sulfate [tex]\(\text{Na}_2\text{SO}_4\)[/tex], the cations are [tex]\(\text{Na}^+\)[/tex] and the anion is [tex]\(\text{SO}_4^{2-}\)[/tex].
3. Swap the Cations:
- The [tex]\(\text{Ba}^{2+}\)[/tex] will pair with the [tex]\(\text{SO}_4^{2-}\)[/tex] to form Barium sulfate ([tex]\(\text{BaSO}_4\)[/tex]).
- The two [tex]\(\text{Na}^+\)[/tex] will pair with the two [tex]\(\text{NO}_3^-\)[/tex] to form Sodium nitrate ([tex]\(\text{NaNO}_3\)[/tex]).
4. Write the Unbalanced Equation:
- [tex]\(\text{Ba}(\text{NO}_3)_2 + \text{Na}_2\text{SO}_4 \rightarrow \text{NaNO}_3 + \text{BaSO}_4\)[/tex]
5. Balance the Chemical Equation:
- To balance the equation, ensure that the same number of each type of atom appears on both sides. We have:
[tex]\[ \text{Ba}(\text{NO}_3)_2 + \text{Na}_2\text{SO}_4 \rightarrow 2\text{NaNO}_3 + \text{BaSO}_4 \][/tex]
- Now, the equation is balanced with:
- 1 Barium atom on each side,
- 2 Nitrate ions on each side,
- 2 Sodium atoms on each side,
- 1 Sulfate ion on each side.
6. Determine the Products:
- The balanced chemical equation confirms that the products are Sodium nitrate ([tex]\(\text{NaNO}_3\)[/tex]) and Barium sulfate ([tex]\(\text{BaSO}_4\)[/tex]).
So, during the replacement reaction of [tex]\(\text{Ba}(\text{NO}_3)_2\)[/tex] and [tex]\(\text{Na}_2\text{SO}_4\)[/tex], the products formed are [tex]\(\text{NaNO}_3\)[/tex] and [tex]\(\text{BaSO}_4\)[/tex].
Reviewing the answer choices:
- [tex]\(2 \text{BaNa} + 2 \text{NO}_3\text{SO}_4\)[/tex]
- [tex]\(2 \text{NaNO}_3 + \text{BaSO}_4\)[/tex]
- [tex]\(\text{NaNO}_3 + \text{BaSO}_4\)[/tex]
- [tex]\(\text{BaNa}_2 + (\text{NO}_3)_2\text{SO}_4\)[/tex]
The correct answer is:
[tex]\[ 2 \text{NaNO}_3 + \text{BaSO}_4 \][/tex]
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