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What are the solutions of this quadratic equation?

[tex]\[ x^2 - 10x = -34 \][/tex]

A. [tex]\( x = -8, -2 \)[/tex]

B. [tex]\( x = 5 \pm 3i \)[/tex]

C. [tex]\( x = -5 \pm 3i \)[/tex]

D. [tex]\( x = -5 \pm \sqrt{59} \)[/tex]

Sagot :

To find the solutions to the quadratic equation [tex]\( x^2 - 10x = -34 \)[/tex], we'll follow these steps:

1. Rewrite the equation in standard quadratic form.

First, bring all terms to one side of the equation to set it to zero:
[tex]\[ x^2 - 10x + 34 = 0 \][/tex]

2. Identify coefficients for the quadratic formula.

The standard quadratic equation is [tex]\( ax^2 + bx + c = 0 \)[/tex]. In this equation:
[tex]\[ a = 1, \quad b = -10, \quad c = 34 \][/tex]

3. Use the quadratic formula.

The quadratic formula is:
[tex]\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \][/tex]

Substitute in the coefficients [tex]\( a \)[/tex], [tex]\( b \)[/tex], and [tex]\( c \)[/tex]:
[tex]\[ x = \frac{-(-10) \pm \sqrt{(-10)^2 - 4 \cdot 1 \cdot 34}}{2 \cdot 1} \][/tex]

4. Simplify the equation.

Calculate inside the square root:
[tex]\[ x = \frac{10 \pm \sqrt{100 - 136}}{2} \][/tex]
[tex]\[ x = \frac{10 \pm \sqrt{-36}}{2} \][/tex]

Simplify the expression under the square root:
[tex]\[ x = \frac{10 \pm \sqrt{36} \cdot i}{2} \][/tex]
[tex]\[ x = \frac{10 \pm 6i}{2} \][/tex]

5. Split the equation into two solutions.

[tex]\[ x = \frac{10 + 6i}{2} \quad \text{and} \quad x = \frac{10 - 6i}{2} \][/tex]

Simplify each fraction:
[tex]\[ x = 5 + 3i \quad \text{and} \quad x = 5 - 3i \][/tex]

So, the solutions to the equation [tex]\( x^2 - 10x = -34 \)[/tex] are:
[tex]\[ x = 5 \pm 3i \][/tex]

Therefore, the correct answer is B. [tex]\( x = 5 \pm 3i \)[/tex].