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Let [tex]$d(t)$[/tex] be the total number of miles Joanna has cycled, and let [tex]$t$[/tex] represent the number of hours before stopping for a break during her ride.
[tex]\[ d(t) = 12t + 20 \][/tex]

So, [tex]$d(4) = \square$[/tex]. This means that after [tex]$\square$[/tex] hours, Joanna [tex][tex]$\square$[/tex][/tex].

Sagot :

GinnyAnswer
To solve this problem, we need to substitute [tex]\( t = 4 \)[/tex] into the function [tex]\( d(t) = 12t + 20 \)[/tex].

Step-by-step:

1. Start with the function [tex]\( d(t) = 12t + 20 \)[/tex].
2. Substitute [tex]\( t = 4 \)[/tex] into the function: [tex]\( d(4) = 12 \cdot 4 + 20 \)[/tex].
3. Simplify the expression: [tex]\( 12 \cdot 4 = 48 \)[/tex].
4. Add the constant: [tex]\( 48 + 20 = 68 \)[/tex].

Therefore, [tex]\( d(4) = 68 \)[/tex].

This means that after 4 hours, Joanna has cycled 68 miles.

So, the correct answers to the blanks are:

1. [tex]\( d(4) = 68 \)[/tex]
2. After 4 hours
3. Joanna has cycled 68 miles
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