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Student Worksheet: Modeling Nuclear Changes

\begin{tabular}{|c|c|c|c|c|c|c|c|c|}
\hline
& \multicolumn{4}{|c|}{Initial} & \multicolumn{4}{|c|}{Final} \\
\hline
& \begin{tabular}{l}
Element(s) \\ and Particles \\ (if applicable)
\end{tabular}
& \begin{tabular}{l}
Number of \\ Protons
\end{tabular}
& \begin{tabular}{l}
Number of \\ Neutrons
\end{tabular}
& \begin{tabular}{l}
Total Mass \\ of \\ Reactants
\end{tabular}
& \begin{tabular}{l}
Element(s) \\ and Particles \\ (if applicable)
\end{tabular}
& \begin{tabular}{l}
Number of \\ Protons
\end{tabular}
& \begin{tabular}{l}
Number of \\ Neutrons
\end{tabular}
& \begin{tabular}{l}
Total Mass \\ of \\ Products
\end{tabular} \\
\hline

\multirow{2}{}{\begin{tabular}{l}
Alpha \\ decay
\end{tabular}}
& \multirow{2}{
}{Polonium} & & & & Lead & & & \\
\hline
& & & & & Alpha particle & & & \\
\hline

\multirow{2}{}{\begin{tabular}{l}
Beta-plus \\ decay
\end{tabular}}
& \multirow{2}{
}{Sodium} & & & & Neon & & & \\
\hline
& & & & & Positron & & & \\
\hline

\multirow{2}{}{\begin{tabular}{l}
Beta-minus \\ decay
\end{tabular}}
& \multirow{2}{
}{Sodium} & & & & Magnesium & & & \\
\hline
& & & & & [tex]$\beta$[/tex] particle & & & \\
\hline

\multirow{3}{}{\begin{tabular}{l}
Gamma \\ radiation
\end{tabular}}
& \multirow{3}{
}{Cobalt} & & & & Nickel & & & \\
\hline
& & & & & Gamma radiation & & & \\
\hline
& & & & & [tex]$\beta$[/tex] particle & & & \\
\hline

\multirow{3}{}{Fission}
& Uranium & & & & Barium & & & \\
\hline
& Neutron & & & & Krypton & & & \\
\hline
& Neutron & & & & Neutrons & & & \\
\hline

\multirow{2}{
}{Fusion}
& Deuterium & & & & Helium & & & \\
\hline
& Tritium & & & & Neutron & & & \\
\hline
\end{tabular}

Sagot :

Certainly! Let's break down and solve the initial part of the worksheet which involves the alpha decay of Polonium.

### Alpha Decay of Polonium:

#### Initial Information:
1. Element: Polonium
2. Number of Protons: 84
3. Number of Neutrons: 125
4. Total Mass of Reactants:
- Total Mass = Number of Protons + Number of Neutrons
- Total Mass = 84 protons + 125 neutrons = 209 units

#### Decay Process:
1. Element and Particles formed after decay:
- When Polonium-209 undergoes alpha decay, it loses an alpha particle, which is essentially a Helium-4 nucleus (2 protons and 2 neutrons).

#### Final Information:
1. Element: Lead
- The resulting element is Lead (Pb) because atomic number changes from 84 (Po) to 82 (Pb) after losing 2 protons.

2. Alpha Particle:
- Protons: 2
- Neutrons: 2

3. Number of Protons:
- Lead: 82
- Alpha Particle: 2

4. Number of Neutrons:
- Lead: 125 (Initial neutrons) - 2 (alpha particle neutrons) = 123

5. Total Mass of Products:
- Find total mass for each product separately and then sum those:
- Lead: [tex]\(82\, (\text{protons}) + 123\, (\text{neutrons}) = 205\)[/tex]
- Alpha Particle: [tex]\(2\, (\text{protons}) + 2\, (\text{neutrons}) = 4\)[/tex]
- Therefore, total mass of products [tex]\( = 205 + 4 = 209\)[/tex] units.

By comparing total masses and number of particles, we confirm that the mass and particle numbers remain consistent before and after the decay, indicating conservation of mass and atomic particles.

Here's the filled-in initial and final states for the Polonium alpha decay process in the table:

| | \multicolumn{4}{|c|}{Initial} | \multicolumn{4}{|c|}{Final} |
|-------------|---------------------------------------------------------------------------------------------------------------|------------------------------------------------------------------------------------------------------------------------------|
| | Element(s) and Particles (if applicable) | Number of Protons | Number of Neutrons | Total Mass of Reactants | Element(s) and Particles (if applicable) | Number of Protons | Number of Neutrons | Total Mass of Products |
|-------------|-----------------------------------------|-------------------|-------------------|------------------------|-------------------------------------------|-------------------|-------------------|------------------------|
| Alpha decay | Polonium | 84 | 125 | 209 | Lead | 82 | 123 | 205 |
| | | | | | Alpha particle | 2 | 2 | 4 |

This step-by-step approach should help you understand and solve the subsequent parts of your worksheet.