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One car has twice the mass of another. The heavier car is travelling at twice the speed of the lighter car. How many times more than the kinetic energy of the lighter car is the kinetic energy of the heavier car?

Sagot :

MathPhys

Answer:

8

Explanation:

Kinetic energy (KE) is equal to half the mass (m) times the square of the speed (v).

KE = ½ mv²

If the mass of the lighter car is M, and its speed is V, then its kinetic energy is:

KE₁ = ½ MV²

If the heavier car has a mass 2M and a speed 2V, then its kinetic energy is:

KE₂ = ½ (2M) (2V)²

KE₂ = 4 MV²

The ratio is:

KE₂ / KE₁ = (4 MV²) / (½ MV²)

KE₂ / KE₁ = 8

The heavier car has 8 times more kinetic energy than the lighter car.

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