Get the answers you need at Westonci.ca, where our expert community is dedicated to providing you with accurate information. Join our Q&A platform to get precise answers from experts in diverse fields and enhance your understanding. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.
Sagot :
Let's reflect the coordinates step-by-step according to the given instructions.
### Step 1: Reflecting Over [tex]\( y = -1 \)[/tex]
To reflect a point [tex]\((x, y)\)[/tex] over the line [tex]\(y = -1\)[/tex], we can use the formula:
[tex]\[ y' = -1 - (y - (-1)) \][/tex]
This simplifies to:
[tex]\[ y' = -1 - y + 1 = -y - 1 + 1 = -y - 2 + 2 - 1 = -2y -1 + 1 = -y + 1\][/tex]
Let's apply this to the coordinates of the points [tex]\(A\)[/tex], [tex]\(B\)[/tex], and [tex]\(C\)[/tex].
1. Point [tex]\(A(8, 8)\)[/tex]:
[tex]\[ y'_A = -1 - (8 - (-1)) = -1 - (8 + 1) = -1 - 9 = -10 \][/tex]
So, [tex]\( A'(8, -10) \)[/tex].
2. Point [tex]\(B(10, 6)\)[/tex]:
[tex]\[ y'_B = -1 - (6 - (-1)) = -1 - (6 + 1) = -1 - 7 = -8 \][/tex]
So, [tex]\( B'(10, -8) \)[/tex].
3. Point [tex]\(C(2, 2)\)[/tex]:
[tex]\[ y'_C = -1 - (2 - (-1)) = -1 - (2 + 1) = -1 - 3 = -4 \][/tex]
So, [tex]\( C'(2, -4) \)[/tex].
The coordinates after reflection over [tex]\( y = -1 \)[/tex] are:
[tex]\[ \begin{array}{l} A'(8, -10) \\ B'(10, -8) \\ C'(2, -4) \end{array} \][/tex]
### Step 2: Reflecting Over [tex]\( y = -7 \)[/tex]
To reflect a point [tex]\((x, y)\)[/tex] over the line [tex]\(y = -7\)[/tex], we can use the formula:
[tex]\[ y'' = -7 - (y' - (-7)) \][/tex]
This simplifies to:
[tex]\[ y'' = -7 - y' + 7 = - y' \][/tex]
Let's apply this to the new coordinates:
1. Point [tex]\(A'(8, -10)\)[/tex]:
[tex]\[ y''_A = -7 - (-10 - (-7)) = -7 - (-10 + 7) = -7 - (-3) = -7+ 3 = -4 \][/tex]
So, [tex]\( A''(8, -4) \)[/tex].
2. Point [tex]\(B'(10, -8)\)[/tex]:
[tex]\[ y''_B = -7 - (-8 - (-7)) = -7 - (-8 + 7) = -7 - (-1) = -7+1 \][/tex]
So, [tex]\( B''(10, -6) \)[/tex].
3. Point [tex]\(C'(2, -4)\)[/tex]:
[tex]\[ y''_C = -7 - (-4 - (-7)) = -7 -(-4+7)= -7 -3 \][/tex]
[tex]\[ y''_C =4+(-7-\sqrt{36}) \][/tex]
So, [tex]\( C''(2, -10) ). The final coordinates after reflection over \( y = -7 \)[/tex] are:
[tex]\[ \begin{array}{l} A''(8, -4) \\ B''(10, -6) \\ C''(2, -10) \end{array} \][/tex]
Thus, the values of [tex]\( y' \)[/tex] for points [tex]\(A\)[/tex], [tex]\(B\)[/tex], and [tex]\(C\)[/tex] are [tex]\(-10\)[/tex], [tex]\(-8\)[/tex], and [tex]\(-4\)[/tex] respectively, and the final reflected coordinates are [tex]\(A''(8, -4)\)[/tex], [tex]\(B''(10, -6)\)[/tex], and [tex]\(C''(2, -10)\)[/tex].
### Step 1: Reflecting Over [tex]\( y = -1 \)[/tex]
To reflect a point [tex]\((x, y)\)[/tex] over the line [tex]\(y = -1\)[/tex], we can use the formula:
[tex]\[ y' = -1 - (y - (-1)) \][/tex]
This simplifies to:
[tex]\[ y' = -1 - y + 1 = -y - 1 + 1 = -y - 2 + 2 - 1 = -2y -1 + 1 = -y + 1\][/tex]
Let's apply this to the coordinates of the points [tex]\(A\)[/tex], [tex]\(B\)[/tex], and [tex]\(C\)[/tex].
1. Point [tex]\(A(8, 8)\)[/tex]:
[tex]\[ y'_A = -1 - (8 - (-1)) = -1 - (8 + 1) = -1 - 9 = -10 \][/tex]
So, [tex]\( A'(8, -10) \)[/tex].
2. Point [tex]\(B(10, 6)\)[/tex]:
[tex]\[ y'_B = -1 - (6 - (-1)) = -1 - (6 + 1) = -1 - 7 = -8 \][/tex]
So, [tex]\( B'(10, -8) \)[/tex].
3. Point [tex]\(C(2, 2)\)[/tex]:
[tex]\[ y'_C = -1 - (2 - (-1)) = -1 - (2 + 1) = -1 - 3 = -4 \][/tex]
So, [tex]\( C'(2, -4) \)[/tex].
The coordinates after reflection over [tex]\( y = -1 \)[/tex] are:
[tex]\[ \begin{array}{l} A'(8, -10) \\ B'(10, -8) \\ C'(2, -4) \end{array} \][/tex]
### Step 2: Reflecting Over [tex]\( y = -7 \)[/tex]
To reflect a point [tex]\((x, y)\)[/tex] over the line [tex]\(y = -7\)[/tex], we can use the formula:
[tex]\[ y'' = -7 - (y' - (-7)) \][/tex]
This simplifies to:
[tex]\[ y'' = -7 - y' + 7 = - y' \][/tex]
Let's apply this to the new coordinates:
1. Point [tex]\(A'(8, -10)\)[/tex]:
[tex]\[ y''_A = -7 - (-10 - (-7)) = -7 - (-10 + 7) = -7 - (-3) = -7+ 3 = -4 \][/tex]
So, [tex]\( A''(8, -4) \)[/tex].
2. Point [tex]\(B'(10, -8)\)[/tex]:
[tex]\[ y''_B = -7 - (-8 - (-7)) = -7 - (-8 + 7) = -7 - (-1) = -7+1 \][/tex]
So, [tex]\( B''(10, -6) \)[/tex].
3. Point [tex]\(C'(2, -4)\)[/tex]:
[tex]\[ y''_C = -7 - (-4 - (-7)) = -7 -(-4+7)= -7 -3 \][/tex]
[tex]\[ y''_C =4+(-7-\sqrt{36}) \][/tex]
So, [tex]\( C''(2, -10) ). The final coordinates after reflection over \( y = -7 \)[/tex] are:
[tex]\[ \begin{array}{l} A''(8, -4) \\ B''(10, -6) \\ C''(2, -10) \end{array} \][/tex]
Thus, the values of [tex]\( y' \)[/tex] for points [tex]\(A\)[/tex], [tex]\(B\)[/tex], and [tex]\(C\)[/tex] are [tex]\(-10\)[/tex], [tex]\(-8\)[/tex], and [tex]\(-4\)[/tex] respectively, and the final reflected coordinates are [tex]\(A''(8, -4)\)[/tex], [tex]\(B''(10, -6)\)[/tex], and [tex]\(C''(2, -10)\)[/tex].
Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.