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Sagot :
To find the probability that Stan guessed correctly on at least 2 out of 10 questions in a multiple-choice quiz where each question has 4 answer choices, we need to use the binomial probability formula:
[tex]\[ P(k \text { successes }) = \binom{n}{k} p^k (1 - p)^{n - k} \][/tex]
Here:
- [tex]\( n = 10 \)[/tex] (total number of questions)
- [tex]\( k \)[/tex] is the number of correct guesses
- [tex]\( p = \frac{1}{4} = 0.25 \)[/tex] (probability of guessing a question correctly)
- [tex]\( 1 - p = 0.75 \)[/tex] (probability of guessing a question incorrectly)
The binomial coefficient [tex]\(\binom{n}{k}\)[/tex] is calculated as:
[tex]\[ \binom{n}{k} = \frac{n!}{k! (n - k)!} \][/tex]
We need to sum the probabilities of getting 2 or more questions correct. That means we will calculate the probability for [tex]\( k = 2, 3, \ldots, 10 \)[/tex] and add them together.
The probabilities sum we need is:
[tex]\[ P(k \geq 2) = P(2) + P(3) + \cdots + P(10) \][/tex]
Rather than calculating each term individually, we use the solution we have derived through calculation to find that the probability sum turns out to be approximately [tex]\( 0.756 \)[/tex].
Therefore, the probability that Stan got at least 2 questions correct, rounded to the nearest thousandth, is:
[tex]\[ \boxed{0.756} \][/tex]
[tex]\[ P(k \text { successes }) = \binom{n}{k} p^k (1 - p)^{n - k} \][/tex]
Here:
- [tex]\( n = 10 \)[/tex] (total number of questions)
- [tex]\( k \)[/tex] is the number of correct guesses
- [tex]\( p = \frac{1}{4} = 0.25 \)[/tex] (probability of guessing a question correctly)
- [tex]\( 1 - p = 0.75 \)[/tex] (probability of guessing a question incorrectly)
The binomial coefficient [tex]\(\binom{n}{k}\)[/tex] is calculated as:
[tex]\[ \binom{n}{k} = \frac{n!}{k! (n - k)!} \][/tex]
We need to sum the probabilities of getting 2 or more questions correct. That means we will calculate the probability for [tex]\( k = 2, 3, \ldots, 10 \)[/tex] and add them together.
The probabilities sum we need is:
[tex]\[ P(k \geq 2) = P(2) + P(3) + \cdots + P(10) \][/tex]
Rather than calculating each term individually, we use the solution we have derived through calculation to find that the probability sum turns out to be approximately [tex]\( 0.756 \)[/tex].
Therefore, the probability that Stan got at least 2 questions correct, rounded to the nearest thousandth, is:
[tex]\[ \boxed{0.756} \][/tex]
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