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Find the focus of the parabola [tex]y^2 - 2y = 4x + 3[/tex].

A. [tex](-1, -1)[/tex]
B. [tex](1,1)[/tex]
C. [tex](-1,1)[/tex]
D. [tex](0,1)[/tex]


Sagot :

To find the focus of the parabola given by the equation [tex]\( y^2 - 2y = 4x + 3 \)[/tex], we need to rewrite it in a standard form and use it to determine the focus.

1. Start with the given equation:
[tex]\[ y^2 - 2y = 4x + 3 \][/tex]

2. Rearrange the equation to make it easier to complete the square:
[tex]\[ y^2 - 2y = 4x + 3 \][/tex]
Subtract 4x and 3 from both sides:
[tex]\[ y^2 - 2y - 4x - 3 = 0 \][/tex]

3. Complete the square for the [tex]\( y \)[/tex]-terms:
- Identify the coefficient of [tex]\( y \)[/tex], which is -2.
- Divide -2 by 2, which gives -1.
- Square -1 to get 1.

So, we add and subtract 1 inside the equation:
[tex]\[ y^2 - 2y + 1 - 1 - 4x - 3 = 0 \][/tex]
[tex]\[ (y - 1)^2 - 1 - 4x - 3 = 0 \][/tex]

4. Simplify the equation:
[tex]\[ (y - 1)^2 - 4x - 4 = 0 \][/tex]
Add 4 to both sides to isolate the completed square:
[tex]\[ (y - 1)^2 = 4x + 4 \][/tex]
Rewrite it:
[tex]\[ (y - 1)^2 = 4(x + 1) \][/tex]

5. Express it in the standard form of a parabola:
The form [tex]\((y - k)^2 = 4p(x - h)\)[/tex] represents a parabola that opens to the right if [tex]\( p > 0 \)[/tex].

6. Identify the parameters:
- [tex]\( h = -1 \)[/tex]
- [tex]\( k = 1 \)[/tex]
- [tex]\( 4p = 4 \)[/tex] implies that [tex]\( p = 1 \)[/tex]

7. Find the focus:
The focus [tex]\((h + p, k)\)[/tex] of the parabola is:
[tex]\[ (-1 + 1, 1) = (0, 1) \][/tex]

Therefore, the focus of the parabola [tex]\(y^2 - 2y = 4x + 3\)[/tex] is at:
[tex]\[ \boxed{(0, 1)} \][/tex]