Let's analyze the ball bearings' diameters from each supplier.
Supplier A:
Diameter measurements: 16.23, 16.27, 16.32, 16.33, 16.36, 16.42, 16.45
For Supplier A, the mean diameter is:
[tex]\[
\text{mean}_A = 16.34 \, \text{mm}
\][/tex]
The standard deviation for Supplier A is:
[tex]\[
s_A = 0.08 \, \text{mm}
\][/tex]
Supplier B:
Diameter measurements: 16.18, 16.21, 16.25, 16.32, 16.39, 16.43, 16.45
For Supplier B, the mean diameter is:
[tex]\[
\text{mean}_B = 16.32 \, \text{mm}
\][/tex]
The standard deviation for Supplier B is:
[tex]\[
s_B = 0.11 \, \text{mm}
\][/tex]
Summarizing both findings, we have:
Supplier A:
[tex]\[
\begin{array}{l}
\text{mean} = 16.34 \, \text{mm} \\
s = 0.08 \, \text{mm}
\end{array}
\][/tex]
Supplier B:
[tex]\[
\begin{array}{l}
\text{mean} = 16.32 \, \text{mm} \\
s = 0.11 \, \text{mm}
\end{array}
\][/tex]
