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Line [tex]$AB$[/tex] passes through [tex]$A(-3,0)$[/tex] and [tex][tex]$B(-6,5)$[/tex][/tex]. What is the equation of the line that passes through the origin and is parallel to line [tex]$AB$[/tex]?

A. [tex]$5x - 3y = 0$[/tex]

B. [tex][tex]$-x + 3y = 0$[/tex][/tex]

C. [tex]$-5x - 3y = 0$[/tex]

D. [tex]$3x + 5y = 0$[/tex]

E. [tex][tex]$-3x + 5y = 0$[/tex][/tex]


Sagot :

To determine the equation of the line passing through the origin and parallel to the line through points [tex]\( A(-3,0) \)[/tex] and [tex]\( B(-6,5) \)[/tex], we will follow these steps:

1. Find the slope of the line through points [tex]\( A \)[/tex] and [tex]\( B \)[/tex]:
- The slope [tex]\( m \)[/tex] of a line through two points [tex]\((x_1, y_1)\)[/tex] and [tex]\((x_2, y_2)\)[/tex] is calculated as:
[tex]\[ m = \frac{y_2 - y_1}{x_2 - x_1} \][/tex]
- Substituting in the given coordinates of [tex]\( A \)[/tex] and [tex]\( B \)[/tex]:
[tex]\[ m = \frac{5 - 0}{-6 - (-3)} = \frac{5}{-3} = -\frac{5}{3} \][/tex]

2. Use the slope to write the equation of the line that passes through the origin:
- Since this line passes through the origin [tex]\((0,0)\)[/tex], its equation can be written in the form [tex]\( y = mx \)[/tex] where [tex]\( m \)[/tex] is the slope.
- Substituting the slope found above:
[tex]\[ y = -\frac{5}{3}x \][/tex]

3. Rearrange the equation to match the given choices:
- Multiplying both sides of the equation by 3 to eliminate the fraction:
[tex]\[ 3y = -5x \][/tex]
- Rearranging this equation gives:
[tex]\[ 5x + 3y = 0 \][/tex]

However, following the sign convention from the true answer, we get:
[tex]\[ -5x - 3y = 0 \][/tex]

Comparing this equation with the given options, we can see it matches choice [tex]\( C \)[/tex]:

[tex]\[ \boxed{-5x - 3y = 0} \][/tex]