To determine the correct name for [tex]\( TiO_2 \)[/tex], where the titanium has a charge of +4, follow these steps:
1. Identify the element and its charge:
- The element in question is titanium ([tex]\( Ti \)[/tex]).
- The question specifies that titanium has a charge of +4, which can be written as [tex]\( Ti^{4+} \)[/tex].
2. Identify the other element in the compound:
- In [tex]\( TiO_2 \)[/tex], the other element is oxygen ([tex]\( O \)[/tex]).
- Oxygen typically has a charge of -2, which can be written as [tex]\( O^{2-} \)[/tex].
3. Determine the ratio of titanium to oxygen:
- Since the compound is [tex]\( TiO_2 \)[/tex], this indicates that there are 2 oxygen atoms for every titanium atom.
4. Balance the charges:
- The total positive charge from titanium ([tex]\( Ti^{4+} \)[/tex]) is +4.
- The total negative charge from 2 oxygen atoms [2 x ([tex]\( O^{2-} \)[/tex])] equals -4.
- The charges balance each other out, leading to a neutral compound, which confirms [tex]\( TiO_2 \)[/tex].
5. Name the compound:
- In naming ionic compounds with transition metals (like titanium), the oxidation state of the metal is included in parentheses using Roman numerals.
- Titanium with a +4 charge is written as titanium(IV).
Combining these elements, the correct name for [tex]\( TiO_2 \)[/tex] where titanium has a charge of +4 is titanium(IV) oxide.
