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Sagot :
To rationalize the denominator of [tex]\(\frac{1}{\sqrt{7}}\)[/tex], we need to eliminate the square root from the denominator. We do this by multiplying both the numerator and the denominator by [tex]\(\sqrt{7}\)[/tex].
Let's start by writing down the fraction:
[tex]\[ \frac{1}{\sqrt{7}} \][/tex]
Now, multiply both the numerator and the denominator by [tex]\(\sqrt{7}\)[/tex]:
[tex]\[ \frac{1 \cdot \sqrt{7}}{\sqrt{7} \cdot \sqrt{7}} \][/tex]
Simplifying the denominator, we know that [tex]\(\sqrt{7} \cdot \sqrt{7} = 7\)[/tex], so we get:
[tex]\[ \frac{\sqrt{7}}{7} \][/tex]
Thus, the rationalized fraction simplifies to [tex]\(\frac{\sqrt{7}}{7}\)[/tex].
Examining the provided options:
- (A) [tex]\(\frac{\sqrt{7}}{7}\)[/tex]
- (B) [tex]\(\frac{1}{\sqrt{7}}\)[/tex]
- (C) [tex]\(\frac{\sqrt{7}}{49}\)[/tex]
- (D) [tex]\(\frac{1}{7}\)[/tex]
The correct answer is:
[tex]\[ \boxed{\text{A}} \][/tex]
Let's start by writing down the fraction:
[tex]\[ \frac{1}{\sqrt{7}} \][/tex]
Now, multiply both the numerator and the denominator by [tex]\(\sqrt{7}\)[/tex]:
[tex]\[ \frac{1 \cdot \sqrt{7}}{\sqrt{7} \cdot \sqrt{7}} \][/tex]
Simplifying the denominator, we know that [tex]\(\sqrt{7} \cdot \sqrt{7} = 7\)[/tex], so we get:
[tex]\[ \frac{\sqrt{7}}{7} \][/tex]
Thus, the rationalized fraction simplifies to [tex]\(\frac{\sqrt{7}}{7}\)[/tex].
Examining the provided options:
- (A) [tex]\(\frac{\sqrt{7}}{7}\)[/tex]
- (B) [tex]\(\frac{1}{\sqrt{7}}\)[/tex]
- (C) [tex]\(\frac{\sqrt{7}}{49}\)[/tex]
- (D) [tex]\(\frac{1}{7}\)[/tex]
The correct answer is:
[tex]\[ \boxed{\text{A}} \][/tex]
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