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Use the function [tex]f(x) = 2 - 5x[/tex] to fill in the blanks in the table.

\begin{tabular}{|l|l|}
\hline
[tex]$x$[/tex] & [tex]$f(x)$[/tex] \\
\hline
-2 & \\
\hline
-1 & \\
\hline
0 & \\
\hline
1 & \\
\hline
2 & \\
\hline
\end{tabular}

Sagot :

To fill in the table using the function [tex]\( f(x) = 2 - 5x \)[/tex], we need to evaluate the function at each given value of [tex]\( x \)[/tex]. Let's walk through the process step-by-step for each value:

1. For [tex]\( x = -2 \)[/tex]:
[tex]\[ f(-2) = 2 - 5(-2) = 2 + 10 = 12 \][/tex]
So, when [tex]\( x = -2 \)[/tex], [tex]\( f(x) = 12 \)[/tex].

2. For [tex]\( x = -1 \)[/tex]:
[tex]\[ f(-1) = 2 - 5(-1) = 2 + 5 = 7 \][/tex]
So, when [tex]\( x = -1 \)[/tex], [tex]\( f(x) = 7 \)[/tex].

3. For [tex]\( x = 0 \)[/tex]:
[tex]\[ f(0) = 2 - 5(0) = 2 - 0 = 2 \][/tex]
So, when [tex]\( x = 0 \)[/tex], [tex]\( f(x) = 2 \)[/tex].

4. For [tex]\( x = 1 \)[/tex]:
[tex]\[ f(1) = 2 - 5(1) = 2 - 5 = -3 \][/tex]
So, when [tex]\( x = 1 \)[/tex], [tex]\( f(x) = -3 \)[/tex].

5. For [tex]\( x = 2 \)[/tex]:
[tex]\[ f(2) = 2 - 5(2) = 2 - 10 = -8 \][/tex]
So, when [tex]\( x = 2 \)[/tex], [tex]\( f(x) = -8 \)[/tex].

Now, we can fill in the table with the computed values:

[tex]\[ \begin{tabular}{|l|l|} \hline $x$ & $f(x)$ \\ \hline -2 & 12 \\ \hline -1 & 7 \\ \hline 0 & 2 \\ \hline 1 & -3 \\ \hline 2 & -8 \\ \hline \end{tabular} \][/tex]

This completes the table with the given function [tex]\( f(x) = 2 - 5x \)[/tex].
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