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Sagot :
To determine the maximum safe secondary current for the given transformer, we need to use the formula:
[tex]\[ \text{Current} = \frac{\text{Power (VA)}}{\text{Voltage (V)}} \][/tex]
In this scenario, we have:
- Power (VA) = 40 VA (Volt-Amperes)
- Secondary Voltage (V) = 24 V
Substitute the given values into the formula:
[tex]\[ \text{Current} = \frac{40 \, \text{VA}}{24 \, \text{V}} \][/tex]
Performing this division:
[tex]\[ \text{Current} = 1.67 \, \text{A} \][/tex]
Thus, the maximum safe secondary current for the transformer is [tex]\(1.67 \, \text{A}\)[/tex].
The correct answer is:
D. [tex]\(40 \, \text{VA} \div 24 \, \text{V} = 1.67 \, \text{A}\)[/tex]
[tex]\[ \text{Current} = \frac{\text{Power (VA)}}{\text{Voltage (V)}} \][/tex]
In this scenario, we have:
- Power (VA) = 40 VA (Volt-Amperes)
- Secondary Voltage (V) = 24 V
Substitute the given values into the formula:
[tex]\[ \text{Current} = \frac{40 \, \text{VA}}{24 \, \text{V}} \][/tex]
Performing this division:
[tex]\[ \text{Current} = 1.67 \, \text{A} \][/tex]
Thus, the maximum safe secondary current for the transformer is [tex]\(1.67 \, \text{A}\)[/tex].
The correct answer is:
D. [tex]\(40 \, \text{VA} \div 24 \, \text{V} = 1.67 \, \text{A}\)[/tex]
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