Answered

At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Connect with a community of experts ready to help you find accurate solutions to your questions quickly and efficiently. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

The product of two consecutive integers is 420. Which quadratic equation can be used to find [tex] x [/tex], the lesser number?

A. [tex] x^2 + 1 = 420 [/tex]
B. [tex] x^2 + 2 = 420 [/tex]
C. [tex] x^2 + x = 420 [/tex]
D. [tex] x^2 + 2x = 420 [/tex]

Sagot :

GinnyAnswer
To find the quadratic equation suitable for determining [tex]\( x \)[/tex], the lesser number, you should follow these steps:

1. Define the two consecutive integers. Let the lesser number be [tex]\( x \)[/tex]. Hence, the next consecutive integer will be [tex]\( x + 1 \)[/tex].

2. Write down the product of these two integers. According to the given information, the product of these two integers is 420. Therefore:
[tex]\[ x \cdot (x + 1) = 420 \][/tex]

3. Expand the left-hand side of the equation:
[tex]\[ x^2 + x = 420 \][/tex]

We can now see that the equation [tex]\( x^2 + x = 420 \)[/tex] is the quadratic equation that can be used to find [tex]\( x \)[/tex].

Therefore, the correct quadratic equation is:
[tex]\[ x^2 + x = 420 \][/tex]

So, the answer is:
[tex]\[ x^2 + x = 420 \][/tex]
Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.