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The product of two consecutive integers is 420. Which quadratic equation can be used to find [tex] x [/tex], the lesser number?

A. [tex] x^2 + 1 = 420 [/tex]
B. [tex] x^2 + 2 = 420 [/tex]
C. [tex] x^2 + x = 420 [/tex]
D. [tex] x^2 + 2x = 420 [/tex]

Sagot :

To find the quadratic equation suitable for determining [tex]\( x \)[/tex], the lesser number, you should follow these steps:

1. Define the two consecutive integers. Let the lesser number be [tex]\( x \)[/tex]. Hence, the next consecutive integer will be [tex]\( x + 1 \)[/tex].

2. Write down the product of these two integers. According to the given information, the product of these two integers is 420. Therefore:
[tex]\[ x \cdot (x + 1) = 420 \][/tex]

3. Expand the left-hand side of the equation:
[tex]\[ x^2 + x = 420 \][/tex]

We can now see that the equation [tex]\( x^2 + x = 420 \)[/tex] is the quadratic equation that can be used to find [tex]\( x \)[/tex].

Therefore, the correct quadratic equation is:
[tex]\[ x^2 + x = 420 \][/tex]

So, the answer is:
[tex]\[ x^2 + x = 420 \][/tex]