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Which of the following would form a nonelectrolyte solution in water?

A. [tex]Cu_2SO_4[/tex]
B. [tex]C_6H_{12}O_6[/tex]
C. [tex]NaNO_3[/tex]
D. [tex]KCl[/tex]

Sagot :

GinnyAnswer
Let's evaluate each of the given compounds to determine which one will form a nonelectrolyte solution in water:

1. Cu2SO4 (Copper(II) sulfate):
- This compound is an ionic compound composed of copper cations (Cu2+) and sulfate anions (SO42-).
- Ionic compounds typically dissociate in water into their respective ions, making them strong electrolytes.
- Therefore, Cu2SO4 forms a strong electrolyte in water, not a nonelectrolyte.

2. C6H12O6 (Glucose):
- This compound is a molecular compound known as glucose.
- Molecular compounds can dissolve in water but generally do not dissociate into ions.
- Because glucose does not produce ions in solution, it is considered a nonelectrolyte.
- Therefore, C6H12O6 forms a nonelectrolyte solution in water.

3. NaNO3 (Sodium nitrate):
- This compound is an ionic compound composed of sodium cations (Na+) and nitrate anions (NO3-).
- Similar to other ionic compounds, sodium nitrate dissociates into its ions in water, making it a strong electrolyte.
- Thus, NaNO3 forms a strong electrolyte in water.

4. KCl (Potassium chloride):
- This compound is an ionic compound composed of potassium cations (K+) and chloride anions (Cl-).
- It dissolves in water to produce its ions, making it a strong electrolyte.
- Hence, KCl forms a strong electrolyte in water.

After evaluating each of these compounds, we find that only one compound forms a nonelectrolyte solution in water:

B. C6H12O6 (Glucose).

So, the correct answer to the question is choice B.
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