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Question 9 of 10

A survey asked students whether they have any siblings and pets. The survey data are shown in the relative frequency table.

\begin{tabular}{|c|c|c|c|}
\hline & Siblings & No siblings & Total \\
\hline Pets & 0.3 & 0.15 & 0.45 \\
\hline No pets & 0.45 & 0.1 & 0.55 \\
\hline Total & 0.75 & 0.25 & 1.0 \\
\hline
\end{tabular}

Given that a student does not have a sibling, what is the likelihood that he or she has a pet?

A. [tex]$75\%$[/tex]

B. [tex]$15\%$[/tex]

C. About [tex]$33\%$[/tex]

D. [tex]$60\%$[/tex]

Sagot :

To solve the problem of determining the likelihood that a student who does not have siblings has a pet, we can use the concept of conditional probability. Here’s a step-by-step explanation:

1. Identify the Given Data:
- Probability of having no siblings (P(No siblings)): This is the total proportion of students with no siblings, which is 0.25.
- Probability of having no siblings and having a pet (P(Pets and No siblings)): This is the joint probability, which is 0.15.

2. Formulate the Problem Using Conditional Probability:
- We want to find [tex]\( P(\text{Pets} \mid \text{No siblings}) \)[/tex], which reads as the probability that a student has a pet given that they have no siblings.

3. Apply the Conditional Probability Formula:
- Conditional probability can be defined as:
[tex]\[ P(\text{Pets} \mid \text{No siblings}) = \frac{P(\text{Pets and No siblings})}{P(\text{No siblings})} \][/tex]

4. Substitute the Given Values:
- [tex]\( P(\text{Pets and No siblings}) = 0.15 \)[/tex]
- [tex]\( P(\text{No siblings}) = 0.25 \)[/tex]
- Therefore,
[tex]\[ P(\text{Pets} \mid \text{No siblings}) = \frac{0.15}{0.25} \][/tex]

5. Calculate the Result:
- [tex]\( \frac{0.15}{0.25} = 0.6 \)[/tex]

6. Convert the Probability to a Percentage:
- Since probabilities can also be expressed as percentages, we multiply by 100 to get the percentage:
[tex]\[ 0.6 \times 100 = 60\% \][/tex]

The likelihood that a student who does not have siblings has a pet is [tex]\(60\%\)[/tex].

Therefore, the correct answer to the question is:
D. 60%