Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.
Sagot :
Let’s determine the mass of the truck using the given information: the spring constant ([tex]\(k\)[/tex]) and the frequency ([tex]\(f\)[/tex]) of oscillation.
### Step-by-Step Solution:
1. Understand the Relationship:
The relationship between the spring constant, frequency, and mass in a harmonic oscillator is given by:
[tex]\[ f = \frac{1}{2 \pi} \sqrt{\frac{k}{m}} \][/tex]
where:
- [tex]\( f \)[/tex] is the frequency,
- [tex]\( k \)[/tex] is the spring constant,
- [tex]\( m \)[/tex] is the mass,
- [tex]\( \pi \)[/tex] is a constant (approximately 3.14159).
2. Rearrange the Formula to Solve for Mass ([tex]\(m\)[/tex]):
Starting with the equation:
[tex]\[ f = \frac{1}{2 \pi} \sqrt{\frac{k}{m}} \][/tex]
Rearrange it to solve for the mass [tex]\( m \)[/tex] as follows:
[tex]\[ f \times 2 \pi = \sqrt{\frac{k}{m}} \][/tex]
[tex]\[ (f \times 2 \pi)^2 = \frac{k}{m} \][/tex]
[tex]\[ m = \frac{k}{(f \times 2 \pi)^2} \][/tex]
3. Calculate the Intermediate Values:
Calculate the value of [tex]\( 2 \pi f \)[/tex]:
[tex]\[ 2 \pi f = 2 \times 3.141592653589793 \times 0.429 \approx 2.6965336943312392 \][/tex]
Next, square this result:
[tex]\[ (2 \pi f)^2 = (2.6965336943312392)^2 \approx 7.2656474543235445 \][/tex]
4. Compute the Mass ([tex]\(m\)[/tex]):
Now, use the spring constant [tex]\( k \)[/tex] and the squared frequency calculated above to find the mass [tex]\( m \)[/tex]:
[tex]\[ m = \frac{k}{(2 \pi f)^2} = \frac{24200}{7.2656474543235445} \approx 3330.742394554168 \][/tex]
### Conclusion:
The mass of the truck is approximately [tex]\( 3330.742 \, \text{kg} \)[/tex].
### Step-by-Step Solution:
1. Understand the Relationship:
The relationship between the spring constant, frequency, and mass in a harmonic oscillator is given by:
[tex]\[ f = \frac{1}{2 \pi} \sqrt{\frac{k}{m}} \][/tex]
where:
- [tex]\( f \)[/tex] is the frequency,
- [tex]\( k \)[/tex] is the spring constant,
- [tex]\( m \)[/tex] is the mass,
- [tex]\( \pi \)[/tex] is a constant (approximately 3.14159).
2. Rearrange the Formula to Solve for Mass ([tex]\(m\)[/tex]):
Starting with the equation:
[tex]\[ f = \frac{1}{2 \pi} \sqrt{\frac{k}{m}} \][/tex]
Rearrange it to solve for the mass [tex]\( m \)[/tex] as follows:
[tex]\[ f \times 2 \pi = \sqrt{\frac{k}{m}} \][/tex]
[tex]\[ (f \times 2 \pi)^2 = \frac{k}{m} \][/tex]
[tex]\[ m = \frac{k}{(f \times 2 \pi)^2} \][/tex]
3. Calculate the Intermediate Values:
Calculate the value of [tex]\( 2 \pi f \)[/tex]:
[tex]\[ 2 \pi f = 2 \times 3.141592653589793 \times 0.429 \approx 2.6965336943312392 \][/tex]
Next, square this result:
[tex]\[ (2 \pi f)^2 = (2.6965336943312392)^2 \approx 7.2656474543235445 \][/tex]
4. Compute the Mass ([tex]\(m\)[/tex]):
Now, use the spring constant [tex]\( k \)[/tex] and the squared frequency calculated above to find the mass [tex]\( m \)[/tex]:
[tex]\[ m = \frac{k}{(2 \pi f)^2} = \frac{24200}{7.2656474543235445} \approx 3330.742394554168 \][/tex]
### Conclusion:
The mass of the truck is approximately [tex]\( 3330.742 \, \text{kg} \)[/tex].
We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.