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The function [tex]D(t)[/tex] defines a traveler's distance from home, in miles, as a function of time, in hours.

[tex]\[
D(t) = \left\{
\begin{array}{ll}
300t + 125, & 0 \leq t \ \textless \ 2.5 \\
875, & 2.5 \leq t \leq 3.5 \\
75t + 612.5, & 3.5 \ \textless \ t \leq 6
\end{array}
\right.
\][/tex]

Which times and distances are represented by the function? Select three options.

A. The starting distance, at 0 hours, is 300 miles.
B. At 2 hours, the traveler is 725 miles from home.
C. At 2.5 hours, the traveler is still moving farther from home.
D. At 3 hours, the distance is constant, at 875 miles.
E. The total distance from home after 6 hours is [tex]1,062.5[/tex] miles.

Sagot :

GinnyAnswer
Let's analyze the function [tex]\( D(t) \)[/tex] that defines a traveler's distance from home in miles over time in hours. We will evaluate it at specific times to determine the appropriate options.

1. At 0 hours:

The formula for the distance [tex]\( D(t) \)[/tex] when [tex]\( 0 \leq t < 2.5 \)[/tex] is given by:
[tex]\[ D(t) = 300t + 125 \][/tex]

Plugging in [tex]\( t = 0 \)[/tex]:
[tex]\[ D(0) = 300(0) + 125 = 125 \text{ miles} \][/tex]

So, the starting distance at 0 hours is 125 miles, not 300 miles.

2. At 2 hours:

Using the same formula as for [tex]\( 0 \leq t < 2.5 \)[/tex]:
[tex]\[ D(t) = 300t + 125 \][/tex]

Plugging in [tex]\( t = 2 \)[/tex]:
[tex]\[ D(2) = 300(2) + 125 = 600 + 125 = 725 \text{ miles} \][/tex]

So, at 2 hours, the traveler is 725 miles from home. This statement is correct.

3. At 2.5 hours:

The distance function for [tex]\( 2.5 \leq t \leq 3.5 \)[/tex] is constant:
[tex]\[ D(t) = 875 \][/tex]

Thus, at [tex]\( t = 2.5 \)[/tex]:
[tex]\[ D(2.5) = 875 \text{ miles} \][/tex]

So the traveler is not moving farther from home at 2.5 hours. The distance is constant 875 miles. This statement is incorrect.

4. At 3 hours:

The distance function for [tex]\( 2.5 \leq t \leq 3.5 \)[/tex] remains:
[tex]\[ D(t) = 875 \][/tex]

Thus, at [tex]\( t = 3 \)[/tex]:
[tex]\[ D(3) = 875 \text{ miles} \][/tex]

So, at 3 hours, the distance is indeed constant at 875 miles. This statement is correct.

5. At 6 hours:

The formula for the distance [tex]\( D(t) \)[/tex] when [tex]\( 3.5 < t \leq 6 \)[/tex] is:
[tex]\[ D(t) = 75t + 612.5 \][/tex]

Plugging in [tex]\( t = 6 \)[/tex]:
[tex]\[ D(6) = 75(6) + 612.5 = 450 + 612.5 = 1062.5 \text{ miles} \][/tex]

So, the total distance from home after 6 hours is 1062.5 miles. This statement is correct.

### Summary:
The correct statements are:
1. At 2 hours, the traveler is 725 miles from home.
2. At 3 hours, the distance is constant, at 875 miles.
3. The total distance from home after 6 hours is 1062.5 miles.
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