Answered

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A particle with charge 4.80×10⁻¹⁹ C is placed on the x axis in a region where the electric potential due to other charges increases in the +x direction but does not change in the y or z direction. The particle, initially at rest, is acted upon only by the electric force and moves from point a to point b along the x axis, increasing its kinetic energy by 1.60×10⁻¹⁹ J . In what direction and through what potential difference Vb−Va does the particle move?
A. The particle moves to the left through a potential difference of Vb−Va= 0.333 V .
B. The particle moves to the left through a potential difference of Vb−Va= -0.333 V
C. The particle moves to the right through a potential difference of Vb−Va= 0.333 V .
D. The particle moves to the right through a potential difference of Vb−Va= -0.333 V .
E. The particle moves to the left through a potential difference of Vb−Va= 3.33 V .
F. The particle moves to the right through a potential difference of Vb−Va= -3.33 V .

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