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\begin{tabular}{|c|c|}
\hline
[tex]$x$[/tex] & [tex]$f(x)$[/tex] \\
\hline
-3 & 18 \\
\hline
-2 & 3 \\
\hline
-1 & 0 \\
\hline
0 & 3 \\
\hline
1 & 6 \\
\hline
2 & 3 \\
\hline
\end{tabular}

Using only the values given in the table for the function [tex]$f(x)$[/tex], what is the largest interval of [tex]$x$[/tex] values where the function is increasing?

[tex]$\square$[/tex]

Sagot :

To find the largest interval of [tex]\( x \)[/tex] values where the function [tex]\( f(x) = -x^3 + 4x + 3 \)[/tex] is increasing, we need to examine the given values of [tex]\( f(x) \)[/tex] provided in the table:

[tex]\[ \begin{array}{|c|c|} \hline x & f(x) \\ \hline -3 & 18 \\ \hline -2 & 3 \\ \hline -1 & 0 \\ \hline 0 & 3 \\ \hline 1 & 6 \\ \hline 2 & 3 \\ \hline \end{array} \][/tex]

Next, we calculate the differences between successive [tex]\( f(x) \)[/tex] values to determine where the function is increasing.

1. Calculate differences between successive [tex]\( f(x) \)[/tex] values:
[tex]\[ \Delta f(x) = f(x_{i+1}) - f(x_i) \][/tex]

- For [tex]\( x = -3 \)[/tex] to [tex]\( x = -2 \)[/tex]:
[tex]\[ f(-2) - f(-3) = 3 - 18 = -15 \][/tex]

- For [tex]\( x = -2 \)[/tex] to [tex]\( x = -1 \)[/tex]:
[tex]\[ f(-1) - f(-2) = 0 - 3 = -3 \][/tex]

- For [tex]\( x = -1 \)[/tex] to [tex]\( x = 0 \)[/tex]:
[tex]\[ f(0) - f(-1) = 3 - 0 = 3 \][/tex]

- For [tex]\( x = 0 \)[/tex] to [tex]\( x = 1 \)[/tex]:
[tex]\[ f(1) - f(0) = 6 - 3 = 3 \][/tex]

- For [tex]\( x = 1 \)[/tex] to [tex]\( x = 2 \)[/tex]:
[tex]\[ f(2) - f(1) = 3 - 6 = -3 \][/tex]

2. Identify the intervals where the differences are positive, indicating the function is increasing:
[tex]\[ \begin{aligned} & \text{Interval from } x = -3 \text{ to } x = -2: \Delta f(x) = -15 \quad (\text{decreasing}) \\ & \text{Interval from } x = -2 \text{ to } x = -1: \Delta f(x) = -3 \quad (\text{decreasing}) \\ & \text{Interval from } x = -1 \text{ to } x = 0: \Delta f(x) = 3 \quad (\text{increasing}) \\ & \text{Interval from } x = 0 \text{ to } x = 1: \Delta f(x) = 3 \quad (\text{increasing}) \\ & \text{Interval from } x = 1 \text{ to } x = 2: \Delta f(x) = -3 \quad (\text{decreasing}) \\ \end{aligned} \][/tex]

From these differences, the intervals where the function is increasing are:
[tex]\[ (-1, 0) \text{ and } (0, 1) \][/tex]

Thus, combining these, we conclude the largest interval where the function is increasing is:
[tex]\[ (-1, 1) \][/tex]

So, the largest interval of [tex]\( x \)[/tex] values where the function [tex]\( f(x) \)[/tex] is increasing is:
[tex]\[ \boxed{(-1, 1)} \][/tex]