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How much heat must be removed from 456 g of water at 25° Celsius to change it into ice at -10.0° Celsius. The specific heat of ice is 2090 J/(kg K) and the latent heat of fusion of water is 33.5 x 10⁴ J/kg. The correct answer is 210 kJ. Would appreciate a clear, step by step explanation.

Sagot :

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