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The equation for distance is [tex]d = st[/tex]. If a car has a speed of [tex]51 \, \text{m/s}[/tex] and travels for 13 seconds, how far does it go?

A. 663 m
B. 3.9 m
C. 810 m
D. 64 m


Sagot :

Sure, let's solve this step-by-step using the given information.

1. Identify the variables:
- The speed [tex]\( s \)[/tex] of the car is 51 meters per second (m/s).
- The time [tex]\( t \)[/tex] the car travels is 13 seconds.

2. Recall the formula for distance:
The formula for calculating distance [tex]\( d \)[/tex] when speed and time are known is:
[tex]\[ d = s \times t \][/tex]

3. Plug in the values into the formula:
- Speed [tex]\( s \)[/tex] = 51 m/s
- Time [tex]\( t \)[/tex] = 13 seconds

Substituting these values into the formula gives:
[tex]\[ d = 51 \times 13 \][/tex]

4. Calculate the distance:
[tex]\[ d = 51 \times 13 = 663 \text{ meters} \][/tex]

So, the car travels 663 meters.

Thus, the correct answer is:
A. 663 m

Answer:

Step-by-step explanation:

  • speed =51ms, time =13s Solution  
  • d=st
  • d=51 x 13
  • d=663 Ans