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The hypotenuse of a [tex]$45^{\circ}-45^{\circ}-90^{\circ}$[/tex] triangle measures 18 cm. What is the length of one leg of the triangle?

A. 9 cm
B. [tex]$9 \sqrt{2}$[/tex] cm
C. 18 cm
D. [tex][tex]$18 \sqrt{2}$[/tex][/tex] cm

Sagot :

To determine the length of one leg in a [tex]\( 45^\circ-45^\circ-90^\circ \)[/tex] triangle when the hypotenuse is given, follow these steps:

1. Understand the properties of a [tex]\( 45^\circ-45^\circ-90^\circ \)[/tex] triangle:
- This type of triangle is an isosceles right triangle, where the two legs are of equal length.
- The relationship between the hypotenuse and each leg in such a triangle is given by the formula:
[tex]\[ \text{Hypotenuse} = \text{Leg} \times \sqrt{2} \][/tex]
- Therefore, the leg can be found by rearranging this formula:
[tex]\[ \text{Leg} = \frac{\text{Hypotenuse}}{\sqrt{2}} \][/tex]

2. Substitute the given hypotenuse length into the formula:
- The hypotenuse length is given as 18 cm.
[tex]\[ \text{Leg} = \frac{18 \, \text{cm}}{\sqrt{2}} \][/tex]

3. Simplify the expression:
- To simplify this expression, we can multiply the numerator and denominator by [tex]\(\sqrt{2}\)[/tex] to rationalize the denominator:
[tex]\[ \text{Leg} = \frac{18 \, \text{cm}}{\sqrt{2}} \times \frac{\sqrt{2}}{\sqrt{2}} = \frac{18 \sqrt{2} \, \text{cm}}{2} = 9 \sqrt{2} \, \text{cm} \][/tex]

4. Evaluate the numerical value (if needed):
- This simplifies the calculation to:
[tex]\[ \text{Leg} = 12.727922061357855 \, \text{cm} \][/tex]

Hence, the length of one leg of the [tex]\( 45^\circ-45^\circ-90^\circ \)[/tex] triangle, given a hypotenuse of 18 cm, is [tex]\( 12.727922061357855 \, \text{cm} \)[/tex].

Therefore, the correct answer choices are:
- To the exact form: [tex]\( 9\sqrt{2} \, \text{cm} \)[/tex]
- To the decimal form: [tex]\( 12.727922061357855 \, \text{cm} \)[/tex]

But based on the value given in the question options, the correct form would be:
[tex]\[ 9\sqrt{2} \, \text{cm} \][/tex]
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