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गर्नुहोस् (Simplify):

[tex]\frac{m^3+1}{m^2-m+1} + \frac{m^3-1}{m^2+m+1}[/tex]


Sagot :

बिलकुल, आइए यो अभिव्यक्तिलाई सरल बनाउँ। हामीसँग निम्न समीकरण छ:

[tex]$\frac{m^3 + 1}{m^2 - m + 1} + \frac{m^3 - 1}{m^2 + m + 1}$[/tex]

हामी ले यसको हर एक पदलाई अलग-अलग विश्लेषण गर्दै यसको सरलीकरण प्रयास गर्छौं।

1. पहिले, [tex]\(m^3 + 1\)[/tex] र [tex]\(m^3 - 1\)[/tex] को जानकारी लिनु पर्दछ।
[tex]\[ m^3 + 1 = (m + 1)(m^2 - m + 1) \][/tex]
[tex]\[ m^3 - 1 = (m - 1)(m^2 + m + 1) \][/tex]

2. अब हामी यो समिकरणमा परिणत गर्दछौं:
[tex]\[ \frac{(m+1)(m^2 - m + 1)}{m^2 - m + 1} + \frac{(m-1)(m^2 + m + 1)}{m^2 + m + 1} \][/tex]

3. अब हामीले समिकरणलाई सरल बनाउऩ, [tex]\((m^2 - m + 1)\)[/tex] र [tex]\((m^2 + m + 1)\)[/tex] को गुणक प्रतिस्थापन गर्दछौं। जब हामीले यो प्रतिस्थापन गर्यौं, यसले अन्य घातांकलाई कटौती गर्न सक्षम बनाउँछ, जसमा केहि सरलीकरण हुनेछ।

इसका परिणाम स्वरूप:

[tex]\[ m + 1 + m - 1 \][/tex]

= [tex]\[ (m + 1) + (m - 1) \][/tex]

4. अन्तमा, हामी सरलीकरण गरिसके पछि शेष:

[tex]\[ = m + m \][/tex]

= [tex]\[ 2m \][/tex]

यसैले, [tex]\( \frac{m^3 + 1}{m^2 - m + 1} + \frac{m^3 - 1}{m^2 + m + 1} \)[/tex] को सरल रूप [tex]\(2m\)[/tex] हुन्छ।
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