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Sagot :
Certainly! Let's go through the steps to solve the inequality [tex]\( 4(4v + 6) < 9v + 3 \)[/tex] step by step:
1. Distribute the 4 on the left side of the inequality:
[tex]\[ 4(4v + 6) < 9v + 3 \][/tex]
Distributing the 4, we get:
[tex]\[ 4 \cdot 4v + 4 \cdot 6 < 9v + 3 \][/tex]
Simplifying further:
[tex]\[ 16v + 24 < 9v + 3 \][/tex]
2. Move all terms involving [tex]\( v \)[/tex] to one side of the inequality:
To isolate [tex]\( v \)[/tex], subtract [tex]\( 9v \)[/tex] from both sides of the inequality:
[tex]\[ 16v + 24 - 9v < 9v + 3 - 9v \][/tex]
Simplifying this:
[tex]\[ 7v + 24 < 3 \][/tex]
3. Move all constant terms to the other side of the inequality:
Subtract 24 from both sides:
[tex]\[ 7v + 24 - 24 < 3 - 24 \][/tex]
Simplifying this:
[tex]\[ 7v < -21 \][/tex]
4. Solve for [tex]\( v \)[/tex]:
Divide both sides by 7:
[tex]\[ v < \frac{-21}{7} \][/tex]
Simplifying this:
[tex]\[ v < -3 \][/tex]
Therefore, the solution to the inequality [tex]\( 4(4v + 6) < 9v + 3 \)[/tex] is:
[tex]\[ v < -3 \][/tex]
1. Distribute the 4 on the left side of the inequality:
[tex]\[ 4(4v + 6) < 9v + 3 \][/tex]
Distributing the 4, we get:
[tex]\[ 4 \cdot 4v + 4 \cdot 6 < 9v + 3 \][/tex]
Simplifying further:
[tex]\[ 16v + 24 < 9v + 3 \][/tex]
2. Move all terms involving [tex]\( v \)[/tex] to one side of the inequality:
To isolate [tex]\( v \)[/tex], subtract [tex]\( 9v \)[/tex] from both sides of the inequality:
[tex]\[ 16v + 24 - 9v < 9v + 3 - 9v \][/tex]
Simplifying this:
[tex]\[ 7v + 24 < 3 \][/tex]
3. Move all constant terms to the other side of the inequality:
Subtract 24 from both sides:
[tex]\[ 7v + 24 - 24 < 3 - 24 \][/tex]
Simplifying this:
[tex]\[ 7v < -21 \][/tex]
4. Solve for [tex]\( v \)[/tex]:
Divide both sides by 7:
[tex]\[ v < \frac{-21}{7} \][/tex]
Simplifying this:
[tex]\[ v < -3 \][/tex]
Therefore, the solution to the inequality [tex]\( 4(4v + 6) < 9v + 3 \)[/tex] is:
[tex]\[ v < -3 \][/tex]
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