Westonci.ca is the best place to get answers to your questions, provided by a community of experienced and knowledgeable experts. Get detailed answers to your questions from a community of experts dedicated to providing accurate information. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
Sure, let's solve the problem step-by-step.
We are given the quadratic expression:
[tex]\[ x^2 + x - 72 \][/tex]
We aim to factor this expression in the form:
[tex]\[ (x + a)(x + b) \][/tex]
### Steps to solve the problem:
1. Identify the coefficient and constant term:
- The quadratic expression is [tex]\( x^2 + x - 72 \)[/tex].
- Here, the coefficient of [tex]\( x^2 \)[/tex] is [tex]\( 1 \)[/tex].
- The coefficient of [tex]\( x \)[/tex] is [tex]\( 1 \)[/tex].
- The constant term is [tex]\( -72 \)[/tex].
2. Determine the conditions for [tex]\( a \)[/tex] and [tex]\( b \)[/tex]:
- We need two numbers [tex]\( a \)[/tex] and [tex]\( b \)[/tex] such that:
[tex]\[ a \cdot b = -72 \][/tex] (product of the numbers should be equal to the constant term)
[tex]\[ a + b = 1 \][/tex] (sum of the numbers should be equal to the coefficient of [tex]\( x \)[/tex])
3. Find the correct pair [tex]\( (a, b) \)[/tex]:
- Consider the factor pairs of [tex]\(-72\)[/tex]. Some of these pairs are:
- [tex]\( (1, -72) \)[/tex]
- [tex]\( (-1, 72) \)[/tex]
- [tex]\( (2, -36) \)[/tex]
- [tex]\( (-2, 36) \)[/tex]
- [tex]\( (3, -24) \)[/tex]
- [tex]\( (-3, 24) \)[/tex]
- [tex]\( (4, -18) \)[/tex]
- [tex]\( (-4, 18) \)[/tex]
- [tex]\( (6, -12) \)[/tex]
- [tex]\( (-6, 12) \)[/tex]
- [tex]\( (8, -9) \)[/tex]
- [tex]\( (-8, 9) \)[/tex]
- From these pairs, the pair that satisfies both conditions is [tex]\( 9 \)[/tex] and [tex]\( -8 \)[/tex]:
[tex]\[ 9 \cdot (-8) = -72 \][/tex]
[tex]\[ 9 + (-8) = 1 \][/tex]
Hence, we found [tex]\( a = 9 \)[/tex] and [tex]\( b = -8 \)[/tex].
### Replace these values in the expression:
[tex]\[ (x + 9)(x - 8) \][/tex]
So, the correct answer to rewrite the given expression [tex]\( x^2 + x - 72 \)[/tex] in the form [tex]\( (x + a)(x + b) \)[/tex] is:
[tex]\[ (x + 9)(x - 8) \][/tex]
We are given the quadratic expression:
[tex]\[ x^2 + x - 72 \][/tex]
We aim to factor this expression in the form:
[tex]\[ (x + a)(x + b) \][/tex]
### Steps to solve the problem:
1. Identify the coefficient and constant term:
- The quadratic expression is [tex]\( x^2 + x - 72 \)[/tex].
- Here, the coefficient of [tex]\( x^2 \)[/tex] is [tex]\( 1 \)[/tex].
- The coefficient of [tex]\( x \)[/tex] is [tex]\( 1 \)[/tex].
- The constant term is [tex]\( -72 \)[/tex].
2. Determine the conditions for [tex]\( a \)[/tex] and [tex]\( b \)[/tex]:
- We need two numbers [tex]\( a \)[/tex] and [tex]\( b \)[/tex] such that:
[tex]\[ a \cdot b = -72 \][/tex] (product of the numbers should be equal to the constant term)
[tex]\[ a + b = 1 \][/tex] (sum of the numbers should be equal to the coefficient of [tex]\( x \)[/tex])
3. Find the correct pair [tex]\( (a, b) \)[/tex]:
- Consider the factor pairs of [tex]\(-72\)[/tex]. Some of these pairs are:
- [tex]\( (1, -72) \)[/tex]
- [tex]\( (-1, 72) \)[/tex]
- [tex]\( (2, -36) \)[/tex]
- [tex]\( (-2, 36) \)[/tex]
- [tex]\( (3, -24) \)[/tex]
- [tex]\( (-3, 24) \)[/tex]
- [tex]\( (4, -18) \)[/tex]
- [tex]\( (-4, 18) \)[/tex]
- [tex]\( (6, -12) \)[/tex]
- [tex]\( (-6, 12) \)[/tex]
- [tex]\( (8, -9) \)[/tex]
- [tex]\( (-8, 9) \)[/tex]
- From these pairs, the pair that satisfies both conditions is [tex]\( 9 \)[/tex] and [tex]\( -8 \)[/tex]:
[tex]\[ 9 \cdot (-8) = -72 \][/tex]
[tex]\[ 9 + (-8) = 1 \][/tex]
Hence, we found [tex]\( a = 9 \)[/tex] and [tex]\( b = -8 \)[/tex].
### Replace these values in the expression:
[tex]\[ (x + 9)(x - 8) \][/tex]
So, the correct answer to rewrite the given expression [tex]\( x^2 + x - 72 \)[/tex] in the form [tex]\( (x + a)(x + b) \)[/tex] is:
[tex]\[ (x + 9)(x - 8) \][/tex]
We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.