Get reliable answers to your questions at Westonci.ca, where our knowledgeable community is always ready to help. Join our Q&A platform to connect with experts dedicated to providing precise answers to your questions in different areas. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.
Sagot :
To find the pH of a solution, you use the formula:
[tex]\[ \text{pH} = -\log_{10} [H^+] \][/tex]
where [tex]\([H^+]\)[/tex] is the concentration of hydrogen ions in moles per liter (M).
Given [tex]\([H^+] = 7.0 \times 10^{-12}\)[/tex] M, we can plug this value into the pH formula:
1. Write the formula for pH:
[tex]\[ \text{pH} = -\log_{10} [H^+] \][/tex]
2. Substitute the given hydrogen ion concentration:
[tex]\[ \text{pH} = -\log_{10} (7.0 \times 10^{-12}) \][/tex]
3. Calculate the logarithm:
By using logarithmic properties, log base 10 of the product can be separated into:
[tex]\[ \log_{10} (7.0 \times 10^{-12}) = \log_{10} 7.0 + \log_{10} 10^{-12} \][/tex]
4. Using known logs and properties:
[tex]\[ \log_{10} 7.0 \approx 0.845 \][/tex]
[tex]\[ \log_{10} 10^{-12} = -12 \][/tex]
Adding these together:
[tex]\[ \log_{10} (7.0 \times 10^{-12}) \approx 0.845 - 12 = -11.1549 \][/tex]
5. Apply the negative sign from the pH formula:
[tex]\[ \text{pH} = -(-11.1549) = 11.1549 \][/tex]
So, the correct answer is:
C. 11.15
[tex]\[ \text{pH} = -\log_{10} [H^+] \][/tex]
where [tex]\([H^+]\)[/tex] is the concentration of hydrogen ions in moles per liter (M).
Given [tex]\([H^+] = 7.0 \times 10^{-12}\)[/tex] M, we can plug this value into the pH formula:
1. Write the formula for pH:
[tex]\[ \text{pH} = -\log_{10} [H^+] \][/tex]
2. Substitute the given hydrogen ion concentration:
[tex]\[ \text{pH} = -\log_{10} (7.0 \times 10^{-12}) \][/tex]
3. Calculate the logarithm:
By using logarithmic properties, log base 10 of the product can be separated into:
[tex]\[ \log_{10} (7.0 \times 10^{-12}) = \log_{10} 7.0 + \log_{10} 10^{-12} \][/tex]
4. Using known logs and properties:
[tex]\[ \log_{10} 7.0 \approx 0.845 \][/tex]
[tex]\[ \log_{10} 10^{-12} = -12 \][/tex]
Adding these together:
[tex]\[ \log_{10} (7.0 \times 10^{-12}) \approx 0.845 - 12 = -11.1549 \][/tex]
5. Apply the negative sign from the pH formula:
[tex]\[ \text{pH} = -(-11.1549) = 11.1549 \][/tex]
So, the correct answer is:
C. 11.15
Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.