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The image produced by a concave mirror is located 20.0 cm in front of the mirror. The focal length of the mirror is 12.0 cm. How far in front of the mirror is the object located?

Sagot :

To determine the position of the object in front of a concave mirror, we can use the mirror formula:

[tex]\[ \frac{1}{f} = \frac{1}{v} + \frac{1}{u} \][/tex]

where:
- [tex]\( f \)[/tex] is the focal length of the mirror,
- [tex]\( v \)[/tex] is the image distance,
- [tex]\( u \)[/tex] is the object distance.

Since we have a concave mirror, both the focal length and image distance are taken as negative values. However, provided values are:
- Image distance, [tex]\( v = 20.0 \)[/tex] cm (in front of the mirror, hence [tex]\( v \)[/tex] should be treated as negative [tex]\( v = -20.0 \text{ cm} \)[/tex]).
- Focal length, [tex]\( f = 12.0 \)[/tex] cm (concave mirror, hence [tex]\( f \)[/tex] should be treated as negative [tex]\( f = -12.0 \text{ cm} \)[/tex]).

We need to find the object distance, [tex]\( u \)[/tex].

Using the mirror formula:

[tex]\[ \frac{1}{f} = \frac{1}{v} + \frac{1}{u} \][/tex]

Substitute the given values into the formula:

[tex]\[ \frac{1}{-12.0} = \frac{1}{-20.0} + \frac{1}{u} \][/tex]

First, calculate [tex]\(\frac{1}{-20.0}\)[/tex]:

[tex]\[ \frac{1}{-20.0} = -0.05 \][/tex]

Now substitute back into the formula and solve for [tex]\(\frac{1}{u}\)[/tex]:

[tex]\[ \frac{1}{-12.0} = -0.05 + \frac{1}{u} \][/tex]

Calculate [tex]\(\frac{1}{-12.0}\)[/tex]:

[tex]\[ \frac{1}{-12.0} = -0.0833 \][/tex]

Now rearrange the equation:

[tex]\[ -0.0833 = -0.05 + \frac{1}{u} \][/tex]

Subtract [tex]\(-0.05\)[/tex] from both sides:

[tex]\[ -0.0833 + 0.05 = \frac{1}{u} \][/tex]

[tex]\[ -0.0333 = \frac{1}{u} \][/tex]

To find [tex]\(u\)[/tex], we take the reciprocal of the result:

[tex]\[ u = \frac{1}{-0.0333} = -30.0 \text{ cm} \][/tex]

The negative sign indicates that the object is located in front of the mirror. So the object distance, [tex]\(u\)[/tex], is:

[tex]\[ 30.0 \text{ cm} \][/tex]

Thus, the object is located 30.0 cm in front of the mirror.