Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Connect with professionals ready to provide precise answers to your questions on our comprehensive Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
Sure, let's solve the given expression step-by-step:
We need to evaluate [tex]\(\operatorname{Tan}\left(a+5^{\circ}\right) \)[/tex] given that:
[tex]\[ \operatorname{Tan}\left(a+5^{\circ}\right)=\sqrt{2 \sin 30^{\circ}+\sec^2 45^{\circ}} \][/tex]
1. Calculate [tex]\(\sin 30^\circ\)[/tex]
[tex]\[ \sin 30^\circ = \frac{1}{2} = 0.5 \][/tex]
2. Calculate [tex]\(\sec 45^\circ\)[/tex]
The secant function is the reciprocal of the cosine function. Therefore:
[tex]\[ \sec 45^\circ = \frac{1}{\cos 45^\circ} = \frac{1}{\frac{\sqrt{2}}{2}} = \sqrt{2} \][/tex]
3. Square [tex]\(\sec 45^\circ\)[/tex]
[tex]\[ \sec^2 45^\circ = (\sqrt{2})^2 = 2 \][/tex]
4. Substitute [tex]\(\sin 30^\circ\)[/tex] and [tex]\(\sec^2 45^\circ\)[/tex] into the expression inside the square root
[tex]\[ 2 \sin 30^\circ + \sec^2 45^\circ = 2 \times 0.5 + 2 = 1 + 2 = 3 \][/tex]
5. Take the square root of the expression
[tex]\[ \sqrt{3} \approx 1.73205 \][/tex]
6. Evaluate [tex]\(\operatorname{Tan}\left(a+5^{\circ}\right)\)[/tex] where the value of [tex]\(a\)[/tex] is 5
We need to find the tan of the angle [tex]\(10^\circ\)[/tex] (since [tex]\(a + 5 = 5 + 5 = 10\)[/tex]):
[tex]\[ \tan(10^\circ) \approx 0.17632698070846498 \][/tex]
So, the step-by-step solution shows that:
[tex]\[ \operatorname{Tan}\left(a+5^{\circ}\right) \approx 0.17632698070846498 \][/tex]
Therefore:
[tex]\[ \operatorname{Tan}\left(10^\circ\right) = \sqrt{2 \sin 30^{\circ} + \sec^2 45^{\circ}} \approx 0.17632698070846498 \][/tex]
We need to evaluate [tex]\(\operatorname{Tan}\left(a+5^{\circ}\right) \)[/tex] given that:
[tex]\[ \operatorname{Tan}\left(a+5^{\circ}\right)=\sqrt{2 \sin 30^{\circ}+\sec^2 45^{\circ}} \][/tex]
1. Calculate [tex]\(\sin 30^\circ\)[/tex]
[tex]\[ \sin 30^\circ = \frac{1}{2} = 0.5 \][/tex]
2. Calculate [tex]\(\sec 45^\circ\)[/tex]
The secant function is the reciprocal of the cosine function. Therefore:
[tex]\[ \sec 45^\circ = \frac{1}{\cos 45^\circ} = \frac{1}{\frac{\sqrt{2}}{2}} = \sqrt{2} \][/tex]
3. Square [tex]\(\sec 45^\circ\)[/tex]
[tex]\[ \sec^2 45^\circ = (\sqrt{2})^2 = 2 \][/tex]
4. Substitute [tex]\(\sin 30^\circ\)[/tex] and [tex]\(\sec^2 45^\circ\)[/tex] into the expression inside the square root
[tex]\[ 2 \sin 30^\circ + \sec^2 45^\circ = 2 \times 0.5 + 2 = 1 + 2 = 3 \][/tex]
5. Take the square root of the expression
[tex]\[ \sqrt{3} \approx 1.73205 \][/tex]
6. Evaluate [tex]\(\operatorname{Tan}\left(a+5^{\circ}\right)\)[/tex] where the value of [tex]\(a\)[/tex] is 5
We need to find the tan of the angle [tex]\(10^\circ\)[/tex] (since [tex]\(a + 5 = 5 + 5 = 10\)[/tex]):
[tex]\[ \tan(10^\circ) \approx 0.17632698070846498 \][/tex]
So, the step-by-step solution shows that:
[tex]\[ \operatorname{Tan}\left(a+5^{\circ}\right) \approx 0.17632698070846498 \][/tex]
Therefore:
[tex]\[ \operatorname{Tan}\left(10^\circ\right) = \sqrt{2 \sin 30^{\circ} + \sec^2 45^{\circ}} \approx 0.17632698070846498 \][/tex]
Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.