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Anthony surveys a group of students at his school about whether they play a sport. This table shows the results broken down by gender.

\begin{tabular}{|c|c|c|c|}
\hline & Play a sport & \begin{tabular}{c}
Do not play a \\
sport
\end{tabular} & Total \\
\hline Boys & 95 & 45 & 140 \\
\hline Girls & 76 & 59 & 135 \\
\hline Total & 171 & 104 & 275 \\
\hline
\end{tabular}

Are being a girl and playing a sport independent events? Why or why not?

A. Yes, they are independent, because [tex]$P($[/tex] girl [tex]$) \approx 0.49$[/tex] and [tex]$P($[/tex] girl [tex]$\mid$[/tex] plays a sport) [tex]$\approx 0.44$[/tex].

B. No, they are not independent, because [tex]$P($[/tex] girl [tex]$) \approx 0.49$[/tex] and [tex]$P($[/tex] girl [tex]$\mid$[/tex] plays a sport [tex]$) \approx 0.44$[/tex].

C. Yes, they are independent, because [tex]$P($[/tex] girl [tex]$) \approx 0.49$[/tex] and [tex]$P($[/tex] girl [tex]$\mid$[/tex] plays a sport) [tex]$\approx 0.62$[/tex].

D. No, they are not independent, because [tex]$P($[/tex] girl [tex]$) \approx 0.49$[/tex] and [tex]$P($[/tex] girl [tex]$\mid$[/tex] plays a sport [tex]$) \approx 0.62$[/tex].

Sagot :

To determine if being a girl and playing a sport are independent events, we need to compare the probability of being a girl, [tex]\( P(\text{girl}) \)[/tex], with the conditional probability of being a girl given that the student plays a sport, [tex]\( P(\text{girl} \mid \text{plays a sport}) \)[/tex].

Here is our step-by-step approach:

1. Calculate the total number of students, total number of girls, and total number of students playing a sport:

[tex]\[ \text{Total students} = 275 \][/tex]
[tex]\[ \text{Total girls} = 135 \][/tex]
[tex]\[ \text{Total students playing a sport} = 171 \][/tex]
[tex]\[ \text{Girls playing a sport} = 76 \][/tex]

2. Calculate the probability of a student being a girl, [tex]\( P(\text{girl}) \)[/tex]:

[tex]\[ P(\text{girl}) = \frac{\text{Total girls}}{\text{Total students}} = \frac{135}{275} \approx 0.4909 \][/tex]

3. Calculate the conditional probability of being a girl given that the student plays a sport, [tex]\( P(\text{girl} \mid \text{plays a sport}) \)[/tex]:

[tex]\[ P(\text{girl} \mid \text{plays a sport}) = \frac{\text{Girls playing a sport}}{\text{Total students playing a sport}} = \frac{76}{171} \approx 0.4444 \][/tex]

4. Determine if the events are independent:

Two events [tex]\( A \)[/tex] and [tex]\( B \)[/tex] are independent if [tex]\( P(A \mid B) = P(A) \)[/tex]. In this case, we need to check if [tex]\( P(\text{girl} \mid \text{plays a sport}) = P(\text{girl}) \)[/tex].

Comparing the values we have:

[tex]\[ P(\text{girl}) \approx 0.4909 \][/tex]
[tex]\[ P(\text{girl} \mid \text{plays a sport}) \approx 0.4444 \][/tex]

Since [tex]\( 0.4909 \neq 0.4444 \)[/tex], the two probabilities are not equal. Hence, being a girl and playing a sport are not independent events.

Therefore, the correct answer is:
[tex]\[ B. \text{No, they are not independent, because } P(\text{girl}) \approx 0.49 \text{ and } P(\text{girl} \mid \text{plays a sport}) \approx 0.44. \][/tex]