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The table represents a linear function.

[tex]\[
\begin{tabular}{|c|c|}
\hline
$x$ & $y$ \\
\hline
-2 & 8 \\
\hline
-1 & 2 \\
\hline
0 & -4 \\
\hline
1 & -10 \\
\hline
2 & -16 \\
\hline
\end{tabular}
\][/tex]

What is the slope of the function?

A. -6
B. -4
C. 4
D. 6

Sagot :

To determine the slope of the linear function represented by the given table, we need to use the values of two points from the table. The formula to calculate the slope [tex]\( m \)[/tex] of a line passing through two points [tex]\((x_1, y_1)\)[/tex] and [tex]\((x_2, y_2)\)[/tex] is:

[tex]\[ m = \frac{y_2 - y_1}{x_2 - x_1} \][/tex]

Let's choose the first two points from the table:
- The first point is [tex]\((x_1, y_1) = (-2, 8)\)[/tex]
- The second point is [tex]\((x_2, y_2) = (-1, 2)\)[/tex]

Now plug these values into the slope formula:

[tex]\[ m = \frac{2 - 8}{-1 - (-2)} \][/tex]

First, simplify the numerator and the denominator separately:
- Numerator: [tex]\( 2 - 8 = -6 \)[/tex]
- Denominator: [tex]\( -1 - (-2) = -1 + 2 = 1 \)[/tex]

So the slope calculation becomes:

[tex]\[ m = \frac{-6}{1} \][/tex]

Therefore, the slope [tex]\( m \)[/tex] is:

[tex]\[ m = -6 \][/tex]

The correct answer is:
[tex]\[ -6 \][/tex]