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Sofia used these steps to find the inverse of function [tex]$f$[/tex].

\begin{tabular}{|l|l|l|}
\hline
Step Number & Function & Step Description \\
\hline
Step 1 & [tex]f(x)=\frac{3 x+4}{8}[/tex] & Given \\
\hline
Step 2 & [tex]y=\frac{3 x+4}{8}[/tex] & Change [tex]f(x)[/tex] to [tex]y[/tex] \\
\hline
Step 3 & [tex]8 x=\frac{3 y+4}{8}[/tex] & Switch [tex]x[/tex] and [tex]y[/tex] \\
\hline
Step 4 & [tex]8 x-4=3 y[/tex] & Multiply each side by 8 \\
\hline
Step 5 & [tex]24 x-12=y[/tex] & Multiply each side by 3 \\
\hline
Step 7 & [tex]24 x-12=f^{-1}(x)[/tex] & Replace [tex]y[/tex] with [tex]f^{-1}(x)[/tex] \\
\hline
\end{tabular}

Use this information to complete the statement.

Sofia made a mistake in step [tex]\square[/tex]. She should have [tex]\square[/tex].


Sagot :

Sofia made a mistake in step [tex]\( 3 \)[/tex]. She should have properly swapped [tex]\( x \)[/tex] and [tex]\( y \)[/tex] and then solved for [tex]\( y \)[/tex]. Specifically, she should have written [tex]\( x = \frac{3y + 4}{8} \)[/tex] and then multiplied both sides by [tex]\( 8 \)[/tex] to isolate [tex]\( y \)[/tex].

Here's the corrected step-by-step solution:

1. Step 1: [tex]\( f(x) = \frac{3x + 4}{8} \)[/tex] (given)
2. Step 2: Replace [tex]\( f(x) \)[/tex] with [tex]\( y \)[/tex] to get [tex]\( y = \frac{3x + 4}{8} \)[/tex].
3. Correct Step 3: Swap [tex]\( x \)[/tex] and [tex]\( y \)[/tex] to find the inverse, giving us [tex]\( x = \frac{3y + 4}{8} \)[/tex].
4. Correct Step 4: Multiply both sides by [tex]\( 8 \)[/tex] to get [tex]\( 8x = 3y + 4 \)[/tex].
5. Subtract [tex]\( 4 \)[/tex] from both sides to isolate the term with [tex]\( y \)[/tex]: [tex]\( 8x - 4 = 3y \)[/tex].
6. Divide both sides by [tex]\( 3 \)[/tex] to solve for [tex]\( y \)[/tex]: [tex]\( y = \frac{8x - 4}{3} \)[/tex].
7. Finally, replace [tex]\( y \)[/tex] with [tex]\( f^{-1}(x) \)[/tex] to express the inverse function:
[tex]\[ f^{-1}(x) = \frac{8x - 4}{3} \][/tex].

So, Sofia's mistake occurred in step [tex]\( 3 \)[/tex], where she should have written [tex]\( x = \frac{3y + 4}{8} \)[/tex] and then multiplied both sides by [tex]\( 8 \)[/tex] to proceed correctly.