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A country's population in 1993 was 83 million. In 2001, it was 87 million. Estimate the population in 2004 using the exponential growth formula. Round your answer to the nearest million.

[tex]\[ P = A e^{kt} \][/tex]

Enter the correct answer:
[tex]\(\square\)[/tex]

Sagot :

To estimate the population in 2004 using the exponential growth formula, let's go through the steps to calculate it.

1. Population Data:
- Initial population ([tex]\(P_0\)[/tex]) in 1993: [tex]\(P_{1993} = 83\)[/tex] million
- Population in 2001: [tex]\(P_{2001} = 87\)[/tex] million
- Years:
- [tex]\(t_1 = 1993\)[/tex]
- [tex]\(t_2 = 2001\)[/tex]
- We need to estimate the population for [tex]\(t_3 = 2004\)[/tex]

2. Growth Rate (k):
We need to find the growth rate [tex]\(k\)[/tex] using the population data.
The exponential growth formula is:
[tex]\[ P(t) = P_0 \cdot e^{k \cdot (t - t_0)} \][/tex]
For 2001:
[tex]\[ P_{2001} = P_{1993} \cdot e^{k \cdot (t_2 - t_1)} \][/tex]
Substitute the known values:
[tex]\[ 87 = 83 \cdot e^{k \cdot (2001 - 1993)} \][/tex]
Simplify the exponent:
[tex]\[ 87 = 83 \cdot e^{k \cdot 8} \][/tex]

3. Solve for [tex]\(k\)[/tex]:
[tex]\[ \frac{87}{83} = e^{8k} \][/tex]
Take the natural logarithm on both sides to isolate [tex]\(k\)[/tex]:
[tex]\[ \ln \left(\frac{87}{83}\right) = 8k \][/tex]
[tex]\[ k = \frac{\ln \left(\frac{87}{83}\right)}{8} \][/tex]
Through this calculation, we find:
[tex]\[ k \approx 0.005883 \][/tex]

4. Estimate Population in 2004:
Use the growth rate [tex]\(k\)[/tex] to estimate the population in 2004.
[tex]\[ P_{2004} = P_{1993} \cdot e^{k \cdot (2004 - 1993)} \][/tex]
Substitute the known values:
[tex]\[ P_{2004} = 83 \cdot e^{0.005883 \cdot 11} \][/tex]
[tex]\[ P_{2004} \approx 83 \cdot e^{0.064713} \][/tex]
Solving this, we get:
[tex]\[ P_{2004} \approx 88.549 \][/tex]

5. Round to the Nearest Million:
The population estimated to the nearest million is:
[tex]\[ P_{2004} \approx 89 \text{ million} \][/tex]

Thus, the estimated population in 2004 is [tex]\(\boxed{89}\)[/tex] million.