At Westonci.ca, we connect you with experts who provide detailed answers to your most pressing questions. Start exploring now! Explore thousands of questions and answers from a knowledgeable community of experts ready to help you find solutions. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
To determine the value of [tex]\((-64)^{\frac{2}{3}}\)[/tex], we need to follow these steps:
1. Understand the properties of exponents and roots: The exponent [tex]\(\frac{2}{3}\)[/tex] means we should first take the cube root of [tex]\(-64\)[/tex] and then square the result. However, with a negative base and a rational exponent, we should expect a complex number.
2. Identify the cube root of [tex]\(-64\)[/tex]: The real cube root of [tex]\(-64\)[/tex] is [tex]\(-4\)[/tex] because [tex]\((-4)^3 = -64\)[/tex]. However, complex numbers will involve using complex cube roots as well.
3. Square the cube root: For a complex number [tex]\((-4)^{\frac{2}{3}}\)[/tex], squaring [tex]\(-4\)[/tex] involves complex analysis where:
- We can rewrite [tex]\(-64\)[/tex] in polar form: [tex]\(64e^{i\pi}\)[/tex].
- Using De Moivre's theorem and properties of exponents, [tex]\((-64)^{2/3} = (64e^{i\pi})^{2/3} = 64^{2/3} \cdot (e^{i\pi})^{2/3}\)[/tex].
- [tex]\(64^{2/3} = 16\)[/tex].
- [tex]\((e^{i\pi})^{2/3} = e^{2i\pi/3}\)[/tex], which corresponds to [tex]\(\pi/3\)[/tex] away from the initial position on the Argand plane, giving us the primary branch [tex]\(5\pi/3\)[/tex] and [tex]\(-\pi/3\)[/tex].
- Therefore, [tex]\(16 \cdot e^{2i\pi/3}\)[/tex] falls within:
Thus, the value of the expression [tex]\((-64)^{\frac{2}{3}}\)[/tex] in complex form turns out to be [tex]\((-7.999999999999996 + 13.856406460551018j)\)[/tex].
This does not directly align with any exact value from the given multiple-choice answers, so based on this complex form, there is no straightforward match to the provided options [tex]\(-16\)[/tex], [tex]\(4\)[/tex], [tex]\(16\)[/tex], or [tex]\(-4\)[/tex]. Perhaps the question might include a misunderstanding or they need to consider complex number solutions.
1. Understand the properties of exponents and roots: The exponent [tex]\(\frac{2}{3}\)[/tex] means we should first take the cube root of [tex]\(-64\)[/tex] and then square the result. However, with a negative base and a rational exponent, we should expect a complex number.
2. Identify the cube root of [tex]\(-64\)[/tex]: The real cube root of [tex]\(-64\)[/tex] is [tex]\(-4\)[/tex] because [tex]\((-4)^3 = -64\)[/tex]. However, complex numbers will involve using complex cube roots as well.
3. Square the cube root: For a complex number [tex]\((-4)^{\frac{2}{3}}\)[/tex], squaring [tex]\(-4\)[/tex] involves complex analysis where:
- We can rewrite [tex]\(-64\)[/tex] in polar form: [tex]\(64e^{i\pi}\)[/tex].
- Using De Moivre's theorem and properties of exponents, [tex]\((-64)^{2/3} = (64e^{i\pi})^{2/3} = 64^{2/3} \cdot (e^{i\pi})^{2/3}\)[/tex].
- [tex]\(64^{2/3} = 16\)[/tex].
- [tex]\((e^{i\pi})^{2/3} = e^{2i\pi/3}\)[/tex], which corresponds to [tex]\(\pi/3\)[/tex] away from the initial position on the Argand plane, giving us the primary branch [tex]\(5\pi/3\)[/tex] and [tex]\(-\pi/3\)[/tex].
- Therefore, [tex]\(16 \cdot e^{2i\pi/3}\)[/tex] falls within:
Thus, the value of the expression [tex]\((-64)^{\frac{2}{3}}\)[/tex] in complex form turns out to be [tex]\((-7.999999999999996 + 13.856406460551018j)\)[/tex].
This does not directly align with any exact value from the given multiple-choice answers, so based on this complex form, there is no straightforward match to the provided options [tex]\(-16\)[/tex], [tex]\(4\)[/tex], [tex]\(16\)[/tex], or [tex]\(-4\)[/tex]. Perhaps the question might include a misunderstanding or they need to consider complex number solutions.
Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.