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Sagot :
To calculate the capacitance of a capacitor when the charge stored on the plates and the voltage across the plates are given, we can use the formula:
[tex]\[ C = \frac{Q}{V} \][/tex]
where:
- [tex]\( C \)[/tex] is the capacitance in Farads (F),
- [tex]\( Q \)[/tex] is the charge in Coulombs (C),
- [tex]\( V \)[/tex] is the voltage in Volts (V).
Given:
- The charge [tex]\( Q \)[/tex] is 200 Coulombs (C),
- The voltage [tex]\( V \)[/tex] is 12 Volts (V).
Now, substitute the given values into the formula:
[tex]\[ C = \frac{200 \, \text{C}}{12 \, \text{V}} \][/tex]
Perform the division:
[tex]\[ C = 16.666666666666668 \, \text{F} \][/tex]
Hence, the capacitance of the capacitor is approximately [tex]\( 16.67 \)[/tex] Farads (F).
[tex]\[ C = \frac{Q}{V} \][/tex]
where:
- [tex]\( C \)[/tex] is the capacitance in Farads (F),
- [tex]\( Q \)[/tex] is the charge in Coulombs (C),
- [tex]\( V \)[/tex] is the voltage in Volts (V).
Given:
- The charge [tex]\( Q \)[/tex] is 200 Coulombs (C),
- The voltage [tex]\( V \)[/tex] is 12 Volts (V).
Now, substitute the given values into the formula:
[tex]\[ C = \frac{200 \, \text{C}}{12 \, \text{V}} \][/tex]
Perform the division:
[tex]\[ C = 16.666666666666668 \, \text{F} \][/tex]
Hence, the capacitance of the capacitor is approximately [tex]\( 16.67 \)[/tex] Farads (F).
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