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Which equation represents the correct net ionic equation for the reaction between [tex]\( \text{Ca(OH)}_2 \)[/tex] and [tex]\( \text{H}_2\text{SO}_4 \)[/tex]?

A. [tex]\( \text{H}^+ + \text{OH}^- \longrightarrow \text{H}_2\text{O} \)[/tex]

B. [tex]\( 2\text{H}^+ + 2\text{OH}^- \longrightarrow \text{H}_2\text{O} \)[/tex]

C. [tex]\( \text{Ca}^{2+} + 2\text{OH}^- + 2\text{H}^+ + \text{SO}_4^{2-} \longrightarrow \text{Ca}^{2+} + \text{SO}_4^{2-} + 2\text{H}_2\text{O} \)[/tex]

D. [tex]\( \text{Ca(OH)}_2 + \text{H}_2\text{SO}_4 \longrightarrow \text{CaSO}_4 + 2\text{H}_2\text{O} \)[/tex]


Sagot :

To determine the correct net ionic equation for the reaction between calcium hydroxide ([tex]\(Ca(OH)_2\)[/tex]) and sulfuric acid ([tex]\(H_2SO_4\)[/tex]), we need to follow these steps:

1. Write the balanced molecular equation:
[tex]\[ Ca(OH)_2 + H_2SO_4 \longrightarrow CaSO_4 + 2H_2O \][/tex]

2. Write the complete ionic equation:
[tex]\[ Ca^{2+}(aq) + 2OH^-(aq) + 2H^+(aq) + SO_4^{2-}(aq) \longrightarrow CaSO_4(s) + 2H_2O(l) \][/tex]

3. Identify and remove the spectator ions:
Spectator ions are ions that appear on both sides of the complete ionic equation without undergoing any chemical change. In this case, [tex]\(Ca^{2+}\)[/tex] and [tex]\(SO_4^{2-}\)[/tex] are spectator ions.

4. Write the net ionic equation by excluding the spectator ions:
[tex]\[ 2OH^-(aq) + 2H^+(aq) \longrightarrow 2H_2O(l) \][/tex]

Simplifying this, we divide by 2:
[tex]\[ OH^-(aq) + H^+(aq) \longrightarrow H_2O(l) \][/tex]

Therefore, the correct net ionic equation for the given reaction is:
[tex]\[ H^+ + OH^- \longrightarrow H_2O \][/tex]

Hence, the correct answer is:
[tex]\[ \boxed{H^+ + OH^- \longrightarrow H_2O} \][/tex]
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