Welcome to Westonci.ca, where your questions are met with accurate answers from a community of experts and enthusiasts. Discover a wealth of knowledge from experts across different disciplines on our comprehensive Q&A platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.
Sagot :
To solve for the possible values of [tex]\( n \)[/tex], let us consider the side lengths of the triangle, which are [tex]\( 2x + 2 \)[/tex] feet, [tex]\( x + 3 \)[/tex] feet, and [tex]\(\pi t\)[/tex].
According to the triangle inequality theorem, for any triangle with sides [tex]\( a \)[/tex], [tex]\( b \)[/tex], and [tex]\( c \)[/tex], the following conditions must hold:
1. [tex]\( a + b > c \)[/tex]
2. [tex]\( a + c > b \)[/tex]
3. [tex]\( b + c > a \)[/tex]
Given the sides [tex]\( 2x + 2 \)[/tex], [tex]\( x + 3 \)[/tex], and [tex]\(\pi t\)[/tex], we apply the triangle inequality theorem:
1. [tex]\((2x + 2) + (x + 3) > \pi t \)[/tex]
2. [tex]\((2x + 2) + \pi t > x + 3 \)[/tex]
3. [tex]\((x + 3) + \pi t > 2x + 2 \)[/tex]
Next, solve these inequalities individually.
First Inequality:
[tex]\[ (2x + 2) + (x + 3) > \pi t \][/tex]
[tex]\[ 3x + 5 > \pi t \][/tex]
Second Inequality:
[tex]\[ (2x + 2) + \pi t > x + 3 \][/tex]
[tex]\[ 2x + 2 + \pi t > x + 3 \][/tex]
[tex]\[ \pi t > x + 1\][/tex]
Third Inequality:
[tex]\[ (x + 3) + \pi t > 2x + 2 \][/tex]
[tex]\[ x + \pi t + 3 > 2x + 2 \][/tex]
[tex]\[ \pi t > x - 1 \][/tex]
After examining the inequalities, observing that [tex]\( \pi t \)[/tex] must be between two bounds, we get:
[tex]\[ x - 1 < \pi t < 3x + 5 \][/tex]
Hence, the values of [tex]\( n \)[/tex] (in terms of [tex]\(\pi t\)[/tex]) should be in the range:
[tex]\[ x - 1 < n < 3x + 5 \][/tex]
So the expression representing the possible values of [tex]\( n \)[/tex] is:
[tex]\[ \boxed{x - 1 < n < 3x + 5} \][/tex]
According to the triangle inequality theorem, for any triangle with sides [tex]\( a \)[/tex], [tex]\( b \)[/tex], and [tex]\( c \)[/tex], the following conditions must hold:
1. [tex]\( a + b > c \)[/tex]
2. [tex]\( a + c > b \)[/tex]
3. [tex]\( b + c > a \)[/tex]
Given the sides [tex]\( 2x + 2 \)[/tex], [tex]\( x + 3 \)[/tex], and [tex]\(\pi t\)[/tex], we apply the triangle inequality theorem:
1. [tex]\((2x + 2) + (x + 3) > \pi t \)[/tex]
2. [tex]\((2x + 2) + \pi t > x + 3 \)[/tex]
3. [tex]\((x + 3) + \pi t > 2x + 2 \)[/tex]
Next, solve these inequalities individually.
First Inequality:
[tex]\[ (2x + 2) + (x + 3) > \pi t \][/tex]
[tex]\[ 3x + 5 > \pi t \][/tex]
Second Inequality:
[tex]\[ (2x + 2) + \pi t > x + 3 \][/tex]
[tex]\[ 2x + 2 + \pi t > x + 3 \][/tex]
[tex]\[ \pi t > x + 1\][/tex]
Third Inequality:
[tex]\[ (x + 3) + \pi t > 2x + 2 \][/tex]
[tex]\[ x + \pi t + 3 > 2x + 2 \][/tex]
[tex]\[ \pi t > x - 1 \][/tex]
After examining the inequalities, observing that [tex]\( \pi t \)[/tex] must be between two bounds, we get:
[tex]\[ x - 1 < \pi t < 3x + 5 \][/tex]
Hence, the values of [tex]\( n \)[/tex] (in terms of [tex]\(\pi t\)[/tex]) should be in the range:
[tex]\[ x - 1 < n < 3x + 5 \][/tex]
So the expression representing the possible values of [tex]\( n \)[/tex] is:
[tex]\[ \boxed{x - 1 < n < 3x + 5} \][/tex]
We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.