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Identify the conjugate acids and bases for the following compounds or ions.
NOTE: Some compounds/ions might have both a conjugate acid and a conjugate base.

\begin{tabular}{|l|l|l|}
\hline
Compound & Conjugate Acid & Conjugate Base \\
\hline
[tex]$H_2O$[/tex] & [tex]$H_3O^+$[/tex] & [tex]$OH^-$[/tex] \\
\hline
[tex]$Cl^-$[/tex] & & \\
\hline
[tex]$HSO_3^-$[/tex] & & \\
\hline
[tex]$H_2PO_4^-$[/tex] & & \\
\hline
\end{tabular}

Sagot :

GinnyAnswer
Sure, let's fill in the missing conjugate acids and bases for the given compounds and ions. Here's the detailed step-by-step solution:

1. For [tex]\( Cl^{-1} \)[/tex]:
- Conjugate Acid: To find the conjugate acid, we add a proton (H⁺) to the compound. Adding H⁺ to [tex]\( Cl^{-1} \)[/tex] gives us [tex]\( HCl \)[/tex].
- Conjugate Base: Chloride ([tex]\( Cl^{-1} \)[/tex]) itself is already a base, and since bases don’t have conjugate bases in this context, it does not have a conjugate base.

Therefore, for [tex]\( Cl^{-1} \)[/tex]:
- Conjugate Acid: [tex]\( HCl \)[/tex]
- Conjugate Base: None (or blank)

2. For [tex]\( HSO_3^{-1} \)[/tex]:
- Conjugate Acid: To find the conjugate acid, we add a proton (H⁺) to the compound. Adding H⁺ to [tex]\( HSO_3^{-1} \)[/tex] gives us [tex]\( H_2SO_3 \)[/tex].
- Conjugate Base: To find the conjugate base, we remove a proton (H⁺) from the compound. Removing H⁺ from [tex]\( HSO_3^{-1} \)[/tex] gives us [tex]\( SO_3^{2-} \)[/tex].

Therefore, for [tex]\( HSO_3^{-1} \)[/tex]:
- Conjugate Acid: [tex]\( H_2SO_3 \)[/tex]
- Conjugate Base: [tex]\( SO_3^{2-} \)[/tex]

3. For [tex]\( H_2PO_4^{-1} \)[/tex]:
- Conjugate Acid: To find the conjugate acid, we add a proton (H⁺) to the compound. Adding H⁺ to [tex]\( H_2PO_4^{-1} \)[/tex] gives us [tex]\( H_3PO_4 \)[/tex].
- Conjugate Base: To find the conjugate base, we remove a proton (H⁺) from the compound. Removing H⁺ from [tex]\( H_2PO_4^{-1} \)[/tex] gives us [tex]\( HPO_4^{2-} \)[/tex].

Therefore, for [tex]\( H_2PO_4^{-1} \)[/tex]:
- Conjugate Acid: [tex]\( H_3PO_4 \)[/tex]
- Conjugate Base: [tex]\( HPO_4^{2-} \)[/tex]

Based on this, we can complete the table as follows:

[tex]\[ \begin{tabular}{|l|l|l|} \hline Compound & Conjugate Acid & Conjugate Base \\ \hline \( H _2 O \) & \( H _3 O^{+} \) & \( OH^{-1} \) \\ \hline \( Cl^{-1} \) & \( HCl \) & \ \\ \hline \( HSO_3^{-1} \) & \( H_2SO_3 \) & \( SO_3^{2-} \) \\ \hline \( H_2PO_4^{-1} \) & \( H_3PO_4 \) & \( HPO_4^{2-} \) \\ \hline \end{tabular} \][/tex]

This table summarizes the conjugate acids and bases for the given compounds or ions, accurately reflecting their chemical behavior in acid-base reactions.
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