Answered

Find the best answers to your questions at Westonci.ca, where experts and enthusiasts provide accurate, reliable information. Explore our Q&A platform to find reliable answers from a wide range of experts in different fields. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

Multiply the binomials.

[tex]\[
\begin{array}{l}
\left(7x^2 - 3y^2\right)\left(x^2 - 8y^2\right) \\
\left(7x^2 - 3y^2\right)\left(x^2 - 8y^2\right) =
\end{array}
\][/tex]

(Simplify your answer.)

Sagot :

GinnyAnswer
Sure, let's multiply the given binomials step by step:

Given binomials:
[tex]\[ (7x^2 - 3y^2)(x^2 - 8y^2) \][/tex]

To simplify, we will use the distributive property, also known as the FOIL method for binomials:

1. First terms: Multiply the first term of each binomial:
[tex]\[ 7x^2 \cdot x^2 = 7x^4 \][/tex]

2. Outer terms: Multiply the outer terms:
[tex]\[ 7x^2 \cdot (-8y^2) = -56x^2y^2 \][/tex]

3. Inner terms: Multiply the inner terms:
[tex]\[ (-3y^2) \cdot x^2 = -3x^2y^2 \][/tex]

4. Last terms: Multiply the last term of each binomial:
[tex]\[ (-3y^2) \cdot (-8y^2) = 24y^4 \][/tex]

Now, add all these products together:
[tex]\[ 7x^4 + (-56x^2y^2) + (-3x^2y^2) + 24y^4 \][/tex]

Combine like terms (the [tex]\(x^2y^2\)[/tex] terms):
[tex]\[ 7x^4 - 56x^2y^2 - 3x^2y^2 + 24y^4 = 7x^4 - 59x^2y^2 + 24y^4 \][/tex]

Therefore, the product of the given binomials is:
[tex]\[ 7x^4 - 59x^2y^2 + 24y^4 \][/tex]
We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.