Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Get detailed and precise answers to your questions from a dedicated community of experts on our Q&A platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
To identify the determinants for the given linear system:
[tex]\[ \begin{array}{l} 5x + 2y = 14 \\ -3x - 5y = 3 \end{array} \][/tex]
we need to perform the following steps:
1. Identify the Coefficients and Constants:
From the given system, the coefficients of [tex]\(x\)[/tex] and [tex]\(y\)[/tex] and the constants are:
[tex]\[ \begin{array}{l} a_{11} = 5, \quad a_{12} = 2, \quad b_1 = 14 \\ a_{21} = -3, \quad a_{22} = -5, \quad b_2 = 3 \end{array} \][/tex]
2. Calculate the Determinant of Matrix [tex]\(A\)[/tex]:
Matrix [tex]\(A\)[/tex] is:
[tex]\[ A = \begin{bmatrix} 5 & 2 \\ -3 & -5 \end{bmatrix} \][/tex]
The determinant of [tex]\(A\)[/tex], denoted as [tex]\(|A|\)[/tex], is calculated using the formula:
[tex]\[ |A| = a_{11}a_{22} - a_{12}a_{21} \][/tex]
Substituting the values:
[tex]\[ |A| = (5)(-5) - (2)(-3) = -25 + 6 = -19 \][/tex]
Therefore,
[tex]\[ |A| = -19 \][/tex]
3. Calculate the Determinant of Matrix [tex]\(A_x\)[/tex]:
Matrix [tex]\(A_x\)[/tex] is obtained by replacing the first column of [tex]\(A\)[/tex] with the constants [tex]\(b_1\)[/tex] and [tex]\(b_2\)[/tex]:
[tex]\[ A_x = \begin{bmatrix} 14 & 2 \\ 3 & -5 \end{bmatrix} \][/tex]
The determinant of [tex]\(A_x\)[/tex], denoted as [tex]\(|A_x|\)[/tex], is calculated using the formula:
[tex]\[ |A_x| = b_1a_{22} - a_{12}b_2 \][/tex]
Substituting the values:
[tex]\[ |A_x| = (14)(-5) - (2)(3) = -70 - 6 = -76 \][/tex]
Therefore,
[tex]\[ |A_x| = -76 \][/tex]
4. Calculate the Determinant of Matrix [tex]\(A_y\)[/tex]:
Matrix [tex]\(A_y\)[/tex] is obtained by replacing the second column of [tex]\(A\)[/tex] with the constants [tex]\(b_1\)[/tex] and [tex]\(b_2\)[/tex]:
[tex]\[ A_y = \begin{bmatrix} 5 & 14 \\ -3 & 3 \end{bmatrix} \][/tex]
The determinant of [tex]\(A_y\)[/tex], denoted as [tex]\(|A_y|\)[/tex], is calculated using the formula:
[tex]\[ |A_y| = a_{11}b_2 - b_1a_{21} \][/tex]
Substituting the values:
[tex]\[ |A_y| = (5)(3) - (14)(-3) = 15 + 42 = 57 \][/tex]
Therefore,
[tex]\[ |A_y| = 57 \][/tex]
So, the determinants for the given linear system are:
[tex]\[ |A| = -19 \][/tex]
[tex]\[ \left|A_x\right| = -76 \][/tex]
[tex]\[ \left|A_y\right| = 57 \][/tex]
[tex]\[ \begin{array}{l} 5x + 2y = 14 \\ -3x - 5y = 3 \end{array} \][/tex]
we need to perform the following steps:
1. Identify the Coefficients and Constants:
From the given system, the coefficients of [tex]\(x\)[/tex] and [tex]\(y\)[/tex] and the constants are:
[tex]\[ \begin{array}{l} a_{11} = 5, \quad a_{12} = 2, \quad b_1 = 14 \\ a_{21} = -3, \quad a_{22} = -5, \quad b_2 = 3 \end{array} \][/tex]
2. Calculate the Determinant of Matrix [tex]\(A\)[/tex]:
Matrix [tex]\(A\)[/tex] is:
[tex]\[ A = \begin{bmatrix} 5 & 2 \\ -3 & -5 \end{bmatrix} \][/tex]
The determinant of [tex]\(A\)[/tex], denoted as [tex]\(|A|\)[/tex], is calculated using the formula:
[tex]\[ |A| = a_{11}a_{22} - a_{12}a_{21} \][/tex]
Substituting the values:
[tex]\[ |A| = (5)(-5) - (2)(-3) = -25 + 6 = -19 \][/tex]
Therefore,
[tex]\[ |A| = -19 \][/tex]
3. Calculate the Determinant of Matrix [tex]\(A_x\)[/tex]:
Matrix [tex]\(A_x\)[/tex] is obtained by replacing the first column of [tex]\(A\)[/tex] with the constants [tex]\(b_1\)[/tex] and [tex]\(b_2\)[/tex]:
[tex]\[ A_x = \begin{bmatrix} 14 & 2 \\ 3 & -5 \end{bmatrix} \][/tex]
The determinant of [tex]\(A_x\)[/tex], denoted as [tex]\(|A_x|\)[/tex], is calculated using the formula:
[tex]\[ |A_x| = b_1a_{22} - a_{12}b_2 \][/tex]
Substituting the values:
[tex]\[ |A_x| = (14)(-5) - (2)(3) = -70 - 6 = -76 \][/tex]
Therefore,
[tex]\[ |A_x| = -76 \][/tex]
4. Calculate the Determinant of Matrix [tex]\(A_y\)[/tex]:
Matrix [tex]\(A_y\)[/tex] is obtained by replacing the second column of [tex]\(A\)[/tex] with the constants [tex]\(b_1\)[/tex] and [tex]\(b_2\)[/tex]:
[tex]\[ A_y = \begin{bmatrix} 5 & 14 \\ -3 & 3 \end{bmatrix} \][/tex]
The determinant of [tex]\(A_y\)[/tex], denoted as [tex]\(|A_y|\)[/tex], is calculated using the formula:
[tex]\[ |A_y| = a_{11}b_2 - b_1a_{21} \][/tex]
Substituting the values:
[tex]\[ |A_y| = (5)(3) - (14)(-3) = 15 + 42 = 57 \][/tex]
Therefore,
[tex]\[ |A_y| = 57 \][/tex]
So, the determinants for the given linear system are:
[tex]\[ |A| = -19 \][/tex]
[tex]\[ \left|A_x\right| = -76 \][/tex]
[tex]\[ \left|A_y\right| = 57 \][/tex]
We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.
