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A new food delivery robot on a college campus is doing test runs at a constant speed of 4 miles per hour. The average test run is 3 miles from the campus cafeteria but varies a distance of 1.5 miles more or less than that.

If [tex]$x$[/tex] is the number of hours the robot is performing a test run, the equation that can be used to find the minimum and maximum time (in hours) for a test run is [tex]|3x - 1.5| = 4[/tex].

For each test run, the minimum time is [tex]\square[/tex] hours and the maximum time is [tex]\square[/tex] hours.

Sagot :

GinnyAnswer
Let's break down the problem step-by-step.

1. Determine the Speed and Distances:
- The robot travels at a constant speed of 4 miles per hour.
- The average distance from the campus cafeteria is 3 miles.
- The distance can vary by 1.5 miles more or less.

2. Calculate the Minimum and Maximum Distances:
- Minimum distance: [tex]\( 3 - 1.5 = 1.5 \)[/tex] miles.
- Maximum distance: [tex]\( 3 + 1.5 = 4.5 \)[/tex] miles.

3. Calculate the Minimum and Maximum Times:
- The time [tex]\( t \)[/tex] is given by the formula: [tex]\( \text{Distance} \div \text{Speed} \)[/tex].
- Minimum time: [tex]\( \frac{1.5}{4} = 0.375 \)[/tex] hours.
- Maximum time: [tex]\( \frac{4.5}{4} = 1.125 \)[/tex] hours.

Therefore, to select the correct answer from each drop-down menu:

For each test run, the minimum time is [tex]\( 0.375 \)[/tex] hours and the maximum time is [tex]\( 1.125 \)[/tex] hours.
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