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1. The negatively charged particle in an atom is the
A. electron.
B. neutron.
C. neutron.
D. proton.

2. How many orbitals are contained in an atom with atomic number A?

The compound formed between [tex]_{14}X[/tex] and [tex]_{10}Y[/tex] is
A. [tex]XY[/tex]
B. [tex]XY_2[/tex]
C. [tex]X_2Y_2[/tex]

Sagot :

GinnyAnswer
Let's go through each question step-by-step.

1. The negatively charged particle in an atom:
- A. Electron
- B. Neutron
- C. Neutron
- D. Proton

Atoms consist of three primary subatomic particles: electrons, protons, and neutrons. Electrons carry a negative charge, protons carry a positive charge, and neutrons are neutral (carry no charge). Therefore, the negatively charged particle in an atom is the electron.

So, the answer is:
A. Electron.

2. How many orbitals are contained in an atom with atomic number [tex]\( A \)[/tex]?

This question does not provide enough specific details about the atomic number [tex]\( A \)[/tex] to determine the number of orbitals directly. The number of orbitals is calculated based on the electron configuration, which in turn depends on the atomic number [tex]\( A \)[/tex]. Without additional information or a more specific value for [tex]\( A \)[/tex], we cannot provide a precise answer here.

3. The compound formed between [tex]\({ }_{14} X\)[/tex] and [tex]\({ }_{10} Y\)[/tex] is:
- 0. [tex]\( XY \)[/tex]
- B. [tex]\( XY_2 \)[/tex]
- C. [tex]\( X_2 Y_2 \)[/tex]

To determine the correct formula of the compound formed between two elements, we look at their valencies or combining capacities.

- [tex]\({ }_{14} X\)[/tex] represents an element with atomic number 14, which is Silicon (Si). Silicon typically forms bonds by sharing four electrons (valency of 4).
- [tex]\({ }_{10} Y\)[/tex] represents an element with atomic number 10, which is Neon (Neon is a noble gas and typically does not form compounds under normal conditions due to its full valence shell).

However, in standard chemistry problems that substitute actual element names with symbols like [tex]\( X \)[/tex] and [tex]\( Y \)[/tex], they may be representing different common elements for the purposes of the question teaching valency. If we consider the likely common valencies from the usual substitutions:

Given usual valency considerations:
- A common approach can suggest [tex]\( X \)[/tex] with a valency of +1 or +4 and [tex]\( Y \)[/tex] with a combining valency suggesting joining to make [tex]\( XY_2 \)[/tex].

Given the usual teaching example stylings, [tex]\( 14X \)[/tex] with [tex]\( 10Y \)[/tex]:
The most likely combined form would be (XY_2).

So, the answer to the compound is:
B. [tex]\( XY_2 \)[/tex]
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