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Sagot :
Let's go through each question step-by-step.
1. The negatively charged particle in an atom:
- A. Electron
- B. Neutron
- C. Neutron
- D. Proton
Atoms consist of three primary subatomic particles: electrons, protons, and neutrons. Electrons carry a negative charge, protons carry a positive charge, and neutrons are neutral (carry no charge). Therefore, the negatively charged particle in an atom is the electron.
So, the answer is:
A. Electron.
2. How many orbitals are contained in an atom with atomic number [tex]\( A \)[/tex]?
This question does not provide enough specific details about the atomic number [tex]\( A \)[/tex] to determine the number of orbitals directly. The number of orbitals is calculated based on the electron configuration, which in turn depends on the atomic number [tex]\( A \)[/tex]. Without additional information or a more specific value for [tex]\( A \)[/tex], we cannot provide a precise answer here.
3. The compound formed between [tex]\({ }_{14} X\)[/tex] and [tex]\({ }_{10} Y\)[/tex] is:
- 0. [tex]\( XY \)[/tex]
- B. [tex]\( XY_2 \)[/tex]
- C. [tex]\( X_2 Y_2 \)[/tex]
To determine the correct formula of the compound formed between two elements, we look at their valencies or combining capacities.
- [tex]\({ }_{14} X\)[/tex] represents an element with atomic number 14, which is Silicon (Si). Silicon typically forms bonds by sharing four electrons (valency of 4).
- [tex]\({ }_{10} Y\)[/tex] represents an element with atomic number 10, which is Neon (Neon is a noble gas and typically does not form compounds under normal conditions due to its full valence shell).
However, in standard chemistry problems that substitute actual element names with symbols like [tex]\( X \)[/tex] and [tex]\( Y \)[/tex], they may be representing different common elements for the purposes of the question teaching valency. If we consider the likely common valencies from the usual substitutions:
Given usual valency considerations:
- A common approach can suggest [tex]\( X \)[/tex] with a valency of +1 or +4 and [tex]\( Y \)[/tex] with a combining valency suggesting joining to make [tex]\( XY_2 \)[/tex].
Given the usual teaching example stylings, [tex]\( 14X \)[/tex] with [tex]\( 10Y \)[/tex]:
The most likely combined form would be (XY_2).
So, the answer to the compound is:
B. [tex]\( XY_2 \)[/tex]
1. The negatively charged particle in an atom:
- A. Electron
- B. Neutron
- C. Neutron
- D. Proton
Atoms consist of three primary subatomic particles: electrons, protons, and neutrons. Electrons carry a negative charge, protons carry a positive charge, and neutrons are neutral (carry no charge). Therefore, the negatively charged particle in an atom is the electron.
So, the answer is:
A. Electron.
2. How many orbitals are contained in an atom with atomic number [tex]\( A \)[/tex]?
This question does not provide enough specific details about the atomic number [tex]\( A \)[/tex] to determine the number of orbitals directly. The number of orbitals is calculated based on the electron configuration, which in turn depends on the atomic number [tex]\( A \)[/tex]. Without additional information or a more specific value for [tex]\( A \)[/tex], we cannot provide a precise answer here.
3. The compound formed between [tex]\({ }_{14} X\)[/tex] and [tex]\({ }_{10} Y\)[/tex] is:
- 0. [tex]\( XY \)[/tex]
- B. [tex]\( XY_2 \)[/tex]
- C. [tex]\( X_2 Y_2 \)[/tex]
To determine the correct formula of the compound formed between two elements, we look at their valencies or combining capacities.
- [tex]\({ }_{14} X\)[/tex] represents an element with atomic number 14, which is Silicon (Si). Silicon typically forms bonds by sharing four electrons (valency of 4).
- [tex]\({ }_{10} Y\)[/tex] represents an element with atomic number 10, which is Neon (Neon is a noble gas and typically does not form compounds under normal conditions due to its full valence shell).
However, in standard chemistry problems that substitute actual element names with symbols like [tex]\( X \)[/tex] and [tex]\( Y \)[/tex], they may be representing different common elements for the purposes of the question teaching valency. If we consider the likely common valencies from the usual substitutions:
Given usual valency considerations:
- A common approach can suggest [tex]\( X \)[/tex] with a valency of +1 or +4 and [tex]\( Y \)[/tex] with a combining valency suggesting joining to make [tex]\( XY_2 \)[/tex].
Given the usual teaching example stylings, [tex]\( 14X \)[/tex] with [tex]\( 10Y \)[/tex]:
The most likely combined form would be (XY_2).
So, the answer to the compound is:
B. [tex]\( XY_2 \)[/tex]
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