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In the interval [tex]$0^{\circ} \leq x \leq 360^{\circ}$[/tex], find the values of [tex]$x$[/tex] for which [tex]$\cos x = 0.7252$[/tex]. Give your answers to the nearest degree.

Sagot :

To find the values of [tex]\( x \)[/tex] for which [tex]\(\cos x = 0.7252\)[/tex] in the interval [tex]\(0^{\circ} \leq x \leq 360^{\circ}\)[/tex], follow these steps:

1. Determine the principal angle:
- Use the inverse cosine function to find the angle whose cosine is [tex]\(0.7252\)[/tex].
- This gives us the principal angle, which lies between [tex]\(0^{\circ}\)[/tex] and [tex]\(180^{\circ}\)[/tex].

2. Calculate the angle:
- The cosine of an angle in degrees that gives [tex]\(0.7252\)[/tex] is approximately [tex]\(44^{\circ}\)[/tex].

3. Find the second angle:
- Recall that the cosine function is positive in the first and fourth quadrants. Therefore, there is another angle in the fourth quadrant that also satisfies the given cosine value.
- The second angle can be found using the symmetry property of the cosine function:
[tex]\[ x = 360^\circ - \text{principal angle} \][/tex]

4. Calculate the second angle in the interval:
- Using the principal angle of [tex]\(44^{\circ}\)[/tex], the second angle is:
[tex]\[ 360^\circ - 44^\circ = 316^\circ \][/tex]

5. Rounding:
- Both angles are already given to the nearest degree.

Thus, the angles [tex]\( x \)[/tex] in the interval [tex]\(0^{\circ} \leq x \leq 360^{\circ}\)[/tex] for which [tex]\(\cos x = 0.7252\)[/tex] are:

[tex]\[ \boxed{44^\circ \text{ and } 316^\circ} \][/tex]