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If [tex]$P(A)=0.60$[/tex] and [tex]$P(B)=0.30$[/tex], then [tex]A[/tex] and [tex]B[/tex] are independent events if

A. [tex][tex]$P(A$[/tex] and $B)=0$[/tex]

B. [tex][tex]$P(A$[/tex] or $B)=0.90$[/tex]

C. [tex][tex]$P(A$[/tex] or $B)=0.18$[/tex]

D. [tex][tex]$P(A$[/tex] and $B)=0.18$[/tex]


Sagot :

To determine if events [tex]\( A \)[/tex] and [tex]\( B \)[/tex] are independent, we need to check if the probability of both events occurring together, [tex]\( P(A \text{ and } B) \)[/tex], equals the product of their individual probabilities, [tex]\( P(A) \)[/tex] and [tex]\( P(B) \)[/tex].

Given:
[tex]\[ P(A) = 0.60 \][/tex]
[tex]\[ P(B) = 0.30 \][/tex]

When two events are independent, the probability of both events happening together is given by:
[tex]\[ P(A \text{ and } B) = P(A) \times P(B) \][/tex]

Let's calculate that:
[tex]\[ P(A \text{ and } B) = 0.60 \times 0.30 \][/tex]
[tex]\[ P(A \text{ and } B) = 0.18 \][/tex]

Therefore, the probability of both events occurring together, assuming they are independent, is [tex]\( 0.18 \)[/tex].

Among the given options, the correct one is:
[tex]\[ D. \quad P(A \text{ and } B) = 0.18 \][/tex]

This indicates that events [tex]\( A \)[/tex] and [tex]\( B \)[/tex] are independent when [tex]\( P(A \text{ and } B) = 0.18 \)[/tex].