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An object, when pushed with a net force F, has an acceleration of 2 m/s^2. Now twice the force is applied to an object that has four times the mass. What will the acceleration be?

Sagot :

Answer:

gg

Explanation:

F = ma

a = F/m

a = 2 m/s2

F → F' = 2F, m → m' = 4m

a' = F'/m' = (2F) / (4m) = (F/m) / 2 = a/2 = (2 m/s2) / 2 = 1 m/s2

MathPhys

Answer:

1 m/s²

Explanation:

According to Newton's second law of motion, the net force on an object (∑F) is equal to the mass (m) times the acceleration (a).

∑F = ma

For the first object, the force is F, the mass is m, and the acceleration is a = 2 m/s².

F = m (2)

F = 2m

For the second object, the force is 2F, and the mass is 4m.

2F = (4m) a

2F = 4ma

Substitute the first equation into the second.

2 (2m) = 4ma

4m = 4ma

a = 1

The acceleration is 1 m/s².

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