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Using Proportions to Compare Shapes

Taylor enlarged triangle [tex]$A$[/tex] proportionally. She made each side 2.5 times as long.

Use the drop-down menus to complete the statements below.

The shortest side in triangle [tex]$B$[/tex] has a measure of [tex]$\square$[/tex] units.

The ratio of a length in triangle [tex]$B$[/tex] to the corresponding length in triangle [tex]$A$[/tex] is equal to [tex]$\square$[/tex].


Sagot :

Certainly! Let's solve this problem step-by-step.

1. Identify the given information:
- We are given that triangle [tex]\( A \)[/tex] was enlarged proportionally.
- Each side of triangle [tex]\( A \)[/tex] was made 2.5 times as long to form triangle [tex]\( B \)[/tex].
- The shortest side in triangle [tex]\( A \)[/tex] measures 25 units.

2. Use the proportion to find the length of the shortest side in triangle [tex]\( B \)[/tex]:
Since each side of triangle [tex]\( A \)[/tex] is enlarged by a factor of 2.5 to form triangle [tex]\( B \)[/tex]:
[tex]\[ \text{Shortest side in triangle } B = \text{Shortest side in triangle } A \times 2.5 \][/tex]
[tex]\[ \text{Shortest side in triangle } B = 25 \times 2.5 \][/tex]
So, the shortest side in triangle [tex]\( B \)[/tex] measures 62.5 units.

3. Ratio of lengths:
The ratio of a length in triangle [tex]\( B \)[/tex] to the corresponding length in triangle [tex]\( A \)[/tex] is given by the scale factor used in the enlargement:
[tex]\[ \text{Ratio} = 2.5 \][/tex]

So, we can complete the statements as follows:

- The shortest side in triangle [tex]\( B \)[/tex] has a measure of 62.5 units.
- The ratio of a length in triangle [tex]\( B \)[/tex] to the corresponding length in triangle [tex]\( A \)[/tex] is equal to 2.5.

Simple as that!