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A rectangular vegetable garden will have a width that is 3 feet less than the length and an area of 54 square feet. If [tex]$x$[/tex] represents the length, then the length can be found by solving the equation:

[tex]x(x-3)=54[/tex]

What is the length, [tex]$x$[/tex], of the garden?

The length is [tex]$\qquad$[/tex] feet.

The solution is [tex]$\square$[/tex].


Sagot :

To find the length [tex]\( x \)[/tex] of the rectangular vegetable garden, we start with the given equation that relates the length and width of the garden to its area:

[tex]\[ x(x - 3) = 54 \][/tex]

1. First, let's expand and rewrite the equation:
[tex]\[ x^2 - 3x = 54 \][/tex]

2. Next, we'll move all terms to one side to set the equation to zero:
[tex]\[ x^2 - 3x - 54 = 0 \][/tex]

3. Now we solve this quadratic equation. We need to find the roots of the equation [tex]\( x^2 - 3x - 54 = 0 \)[/tex]. To do this, we can factorize the quadratic equation:

We look for two numbers that multiply to [tex]\(-54\)[/tex] (the constant term) and add to [tex]\(-3\)[/tex] (the coefficient of [tex]\( x \)[/tex]). Those numbers are [tex]\( -9 \)[/tex] and [tex]\( 6 \)[/tex].

4. Using these numbers, we can write:
[tex]\[ x^2 - 9x + 6x - 54 = 0 \][/tex]

5. Factor by grouping:
[tex]\[ x(x - 9) + 6(x - 9) = 0 \][/tex]

6. Factor out the common term [tex]\((x - 9)\)[/tex]:
[tex]\[ (x - 9)(x + 6) = 0 \][/tex]

7. Set each factor equal to zero to solve for [tex]\( x \)[/tex]:
[tex]\[ x - 9 = 0 \quad \text{or} \quad x + 6 = 0 \][/tex]
[tex]\[ x = 9 \quad \text{or} \quad x = -6 \][/tex]

Since the length of the garden must be a positive value, we discard [tex]\( x = -6 \)[/tex] as it is not physically meaningful in this context.

Thus, the length [tex]\( x \)[/tex] of the garden is [tex]\( 9 \)[/tex] feet.

The length is [tex]\(\boxed{9}\)[/tex] feet.