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Sagot :
To determine how far Sierra moved the couch, we need to make use of the work-energy principle which relates work, force, and distance through the formula [tex]\( W = F \cdot d \)[/tex]. Here:
- [tex]\( W \)[/tex] is the work done, which is 500 joules (J).
- [tex]\( F \)[/tex] is the force applied, which is 250 newtons (N).
- [tex]\( d \)[/tex] is the distance, which we need to find.
Given the formula [tex]\( W = F \cdot d \)[/tex], we can rearrange it to solve for the distance [tex]\( d \)[/tex]:
[tex]\[ d = \frac{W}{F} \][/tex]
Substitute the given values into the formula:
[tex]\[ d = \frac{500 \text{ J}}{250 \text{ N}} \][/tex]
Now, perform the division:
[tex]\[ d = 2 \text{ meters} \][/tex]
Therefore, Sierra moved the couch 2 meters. The correct answer is:
2 m
- [tex]\( W \)[/tex] is the work done, which is 500 joules (J).
- [tex]\( F \)[/tex] is the force applied, which is 250 newtons (N).
- [tex]\( d \)[/tex] is the distance, which we need to find.
Given the formula [tex]\( W = F \cdot d \)[/tex], we can rearrange it to solve for the distance [tex]\( d \)[/tex]:
[tex]\[ d = \frac{W}{F} \][/tex]
Substitute the given values into the formula:
[tex]\[ d = \frac{500 \text{ J}}{250 \text{ N}} \][/tex]
Now, perform the division:
[tex]\[ d = 2 \text{ meters} \][/tex]
Therefore, Sierra moved the couch 2 meters. The correct answer is:
2 m
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