To determine the work done by the eagle in carrying the fish up into the sky, we can use the formula for work:
[tex]\[ W = F \times d \][/tex]
Where:
- [tex]\( W \)[/tex] is the work done,
- [tex]\( F \)[/tex] is the force applied,
- [tex]\( d \)[/tex] is the distance over which the force is applied.
From the problem, we know:
- The force [tex]\( F \)[/tex] applied by the eagle is 90 Newtons.
- The distance [tex]\( d \)[/tex] the fish is carried is 50 meters.
Substitute the given values into the formula:
[tex]\[ W = 90 \, \text{N} \times 50 \, \text{m} \][/tex]
[tex]\[ W = 4500 \, \text{Joules} \][/tex]
Thus, the work done by the eagle on the fish is 4500 Joules.
Out of the given options:
- 40 J
- 59 J
- 140 J
- 4500 J
The correct answer is 4500 J.
